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Two 220 V, 100 W bulbs are connected first in series and then in parallel. Each time the combination is connected to 220 V ac supply line. The power drawn by the combination in each case respectively will be
- a)100 W, 50 W
- b)200 W,150 W
- c)50 W,200 W
- d)50 W,100 W
Correct answer is option 'C'. Can you explain this answer?
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Two 220 V, 100 W bulbs are connected first in series and then in paral...
Given:
Voltage (V) = 220 V
Power (P) = 100 W
When bulbs are connected in series:
- Total voltage (Vt) = 2V = 440 V
- Total resistance (Rt) = R1 + R2
- Power (P) = Vt^2/Rt
- Power (P) = 220*220/(2R) = 100
- R = 484 Ω
- Voltage drop across each bulb (V1, V2) = IR = 110 V
- Power consumed by each bulb (P1, P2) = V1^2/R = V2^2/R = 50 W
- Total power consumed by combination = P1 + P2 = 100 W
When bulbs are connected in parallel:
- Total voltage (Vt) = V = 220 V
- Total resistance (Rt) = (1/R1 + 1/R2)^-1
- Power (P) = V^2/Rt
- Power (P) = 220*220/R = 200
- R = 121 Ω
- Current (I) = V/R = 1.81 A
- Power consumed by bulb 1 (P1) = I^2R1 = 164.7 W
- Power consumed by bulb 2 (P2) = I^2R2 = 35.3 W
- Total power consumed by combination = P1 + P2 = 200 W
Therefore, the power drawn by the combination in each case respectively will be:
- 50 W, 200 W (when connected in parallel)
- 100 W, 50 W (when connected in series)
Hence, option C is the correct answer.
Voltage (V) = 220 V
Power (P) = 100 W
When bulbs are connected in series:
- Total voltage (Vt) = 2V = 440 V
- Total resistance (Rt) = R1 + R2
- Power (P) = Vt^2/Rt
- Power (P) = 220*220/(2R) = 100
- R = 484 Ω
- Voltage drop across each bulb (V1, V2) = IR = 110 V
- Power consumed by each bulb (P1, P2) = V1^2/R = V2^2/R = 50 W
- Total power consumed by combination = P1 + P2 = 100 W
When bulbs are connected in parallel:
- Total voltage (Vt) = V = 220 V
- Total resistance (Rt) = (1/R1 + 1/R2)^-1
- Power (P) = V^2/Rt
- Power (P) = 220*220/R = 200
- R = 121 Ω
- Current (I) = V/R = 1.81 A
- Power consumed by bulb 1 (P1) = I^2R1 = 164.7 W
- Power consumed by bulb 2 (P2) = I^2R2 = 35.3 W
- Total power consumed by combination = P1 + P2 = 200 W
Therefore, the power drawn by the combination in each case respectively will be:
- 50 W, 200 W (when connected in parallel)
- 100 W, 50 W (when connected in series)
Hence, option C is the correct answer.
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Two 220 V, 100 W bulbs are connected first in series and then in parallel. Each time the combination is connected to 220 V ac supply line. The power drawn by the combination in each case respectively will bea)100 W, 50 Wb)200 W,150 Wc)50 W,200 Wd)50 W,100 WCorrect answer is option 'C'. Can you explain this answer?
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Two 220 V, 100 W bulbs are connected first in series and then in parallel. Each time the combination is connected to 220 V ac supply line. The power drawn by the combination in each case respectively will bea)100 W, 50 Wb)200 W,150 Wc)50 W,200 Wd)50 W,100 WCorrect answer is option 'C'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Two 220 V, 100 W bulbs are connected first in series and then in parallel. Each time the combination is connected to 220 V ac supply line. The power drawn by the combination in each case respectively will bea)100 W, 50 Wb)200 W,150 Wc)50 W,200 Wd)50 W,100 WCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two 220 V, 100 W bulbs are connected first in series and then in parallel. Each time the combination is connected to 220 V ac supply line. The power drawn by the combination in each case respectively will bea)100 W, 50 Wb)200 W,150 Wc)50 W,200 Wd)50 W,100 WCorrect answer is option 'C'. Can you explain this answer?.
Two 220 V, 100 W bulbs are connected first in series and then in parallel. Each time the combination is connected to 220 V ac supply line. The power drawn by the combination in each case respectively will bea)100 W, 50 Wb)200 W,150 Wc)50 W,200 Wd)50 W,100 WCorrect answer is option 'C'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Two 220 V, 100 W bulbs are connected first in series and then in parallel. Each time the combination is connected to 220 V ac supply line. The power drawn by the combination in each case respectively will bea)100 W, 50 Wb)200 W,150 Wc)50 W,200 Wd)50 W,100 WCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two 220 V, 100 W bulbs are connected first in series and then in parallel. Each time the combination is connected to 220 V ac supply line. The power drawn by the combination in each case respectively will bea)100 W, 50 Wb)200 W,150 Wc)50 W,200 Wd)50 W,100 WCorrect answer is option 'C'. Can you explain this answer?.
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Two 220 V, 100 W bulbs are connected first in series and then in parallel. Each time the combination is connected to 220 V ac supply line. The power drawn by the combination in each case respectively will bea)100 W, 50 Wb)200 W,150 Wc)50 W,200 Wd)50 W,100 WCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for Two 220 V, 100 W bulbs are connected first in series and then in parallel. Each time the combination is connected to 220 V ac supply line. The power drawn by the combination in each case respectively will bea)100 W, 50 Wb)200 W,150 Wc)50 W,200 Wd)50 W,100 WCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of Two 220 V, 100 W bulbs are connected first in series and then in parallel. Each time the combination is connected to 220 V ac supply line. The power drawn by the combination in each case respectively will bea)100 W, 50 Wb)200 W,150 Wc)50 W,200 Wd)50 W,100 WCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
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