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Two 220 V, 100 W bulbs are connected first in series and then in parallel. Each time the combination is connected to 220 V ac supply line. The power drawn by the combination in each case respectively will be
- a)100 W, 50 W
- b)200 W,150 W
- c)50 W,200 W
- d)50 W,100 W
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
Two 220 V, 100 W bulbs are connected first in series and then in paral...
Series Connection:
In a series connection, the bulbs are connected one after the other, so the same current passes through each bulb. Let's analyze the circuit when the bulbs are connected in series.
Voltage:
When the bulbs are connected in series, the total voltage across the combination will be equal to the sum of the individual voltages across the bulbs.
Since each bulb is connected to a 220 V AC supply line, the total voltage across the combination will also be 220 V.
Current:
In a series circuit, the same current passes through each component. Therefore, the current passing through each bulb will be the same.
Using Ohm's Law, we can calculate the current passing through each bulb.
Given: Voltage (V) = 220 V, Power (P) = 100 W
Using the formula P = IV, we can find the current (I).
100 W = 220 V * I
I = 100 W / 220 V
I ≈ 0.455 A
Power:
In a series circuit, the total power consumed is equal to the sum of the powers consumed by each individual component.
Since both bulbs have the same power rating of 100 W, the total power drawn by the combination will be 100 W + 100 W = 200 W.
Parallel Connection:
In a parallel connection, the bulbs are connected side by side, so the voltage across each bulb is the same. Let's analyze the circuit when the bulbs are connected in parallel.
Voltage:
When the bulbs are connected in parallel, the voltage across each bulb will be the same as the supply voltage, which is 220 V.
Current:
In a parallel circuit, the total current passing through the combination will be equal to the sum of the currents passing through each individual bulb.
Using Ohm's Law, we can calculate the current passing through each bulb.
Given: Voltage (V) = 220 V, Power (P) = 100 W
Using the formula P = IV, we can find the current (I).
100 W = 220 V * I
I = 100 W / 220 V
I ≈ 0.455 A
Since the bulbs are connected in parallel, the total current passing through the combination will be the sum of the currents passing through each bulb, which is 0.455 A + 0.455 A = 0.91 A.
Power:
In a parallel circuit, the total power consumed is equal to the sum of the powers consumed by each individual component.
Since each bulb has a power rating of 100 W, the total power drawn by the combination will be 100 W + 100 W = 200 W.
Therefore, the power drawn by the combination when the bulbs are connected in series is 100 W and 200 W when connected in parallel. Hence, the correct answer is option 'C' - 50 W, 200 W.
In a series connection, the bulbs are connected one after the other, so the same current passes through each bulb. Let's analyze the circuit when the bulbs are connected in series.
Voltage:
When the bulbs are connected in series, the total voltage across the combination will be equal to the sum of the individual voltages across the bulbs.
Since each bulb is connected to a 220 V AC supply line, the total voltage across the combination will also be 220 V.
Current:
In a series circuit, the same current passes through each component. Therefore, the current passing through each bulb will be the same.
Using Ohm's Law, we can calculate the current passing through each bulb.
Given: Voltage (V) = 220 V, Power (P) = 100 W
Using the formula P = IV, we can find the current (I).
100 W = 220 V * I
I = 100 W / 220 V
I ≈ 0.455 A
Power:
In a series circuit, the total power consumed is equal to the sum of the powers consumed by each individual component.
Since both bulbs have the same power rating of 100 W, the total power drawn by the combination will be 100 W + 100 W = 200 W.
Parallel Connection:
In a parallel connection, the bulbs are connected side by side, so the voltage across each bulb is the same. Let's analyze the circuit when the bulbs are connected in parallel.
Voltage:
When the bulbs are connected in parallel, the voltage across each bulb will be the same as the supply voltage, which is 220 V.
Current:
In a parallel circuit, the total current passing through the combination will be equal to the sum of the currents passing through each individual bulb.
Using Ohm's Law, we can calculate the current passing through each bulb.
Given: Voltage (V) = 220 V, Power (P) = 100 W
Using the formula P = IV, we can find the current (I).
100 W = 220 V * I
I = 100 W / 220 V
I ≈ 0.455 A
Since the bulbs are connected in parallel, the total current passing through the combination will be the sum of the currents passing through each bulb, which is 0.455 A + 0.455 A = 0.91 A.
Power:
In a parallel circuit, the total power consumed is equal to the sum of the powers consumed by each individual component.
Since each bulb has a power rating of 100 W, the total power drawn by the combination will be 100 W + 100 W = 200 W.
Therefore, the power drawn by the combination when the bulbs are connected in series is 100 W and 200 W when connected in parallel. Hence, the correct answer is option 'C' - 50 W, 200 W.
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Two 220 V, 100 W bulbs are connected first in series and then in parallel. Each time the combination is connected to 220 V ac supply line. The power drawn by the combination in each case respectively will bea)100 W, 50 Wb)200 W,150 Wc)50 W,200 Wd)50 W,100 WCorrect answer is option 'C'. Can you explain this answer?
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Two 220 V, 100 W bulbs are connected first in series and then in parallel. Each time the combination is connected to 220 V ac supply line. The power drawn by the combination in each case respectively will bea)100 W, 50 Wb)200 W,150 Wc)50 W,200 Wd)50 W,100 WCorrect answer is option 'C'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Two 220 V, 100 W bulbs are connected first in series and then in parallel. Each time the combination is connected to 220 V ac supply line. The power drawn by the combination in each case respectively will bea)100 W, 50 Wb)200 W,150 Wc)50 W,200 Wd)50 W,100 WCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two 220 V, 100 W bulbs are connected first in series and then in parallel. Each time the combination is connected to 220 V ac supply line. The power drawn by the combination in each case respectively will bea)100 W, 50 Wb)200 W,150 Wc)50 W,200 Wd)50 W,100 WCorrect answer is option 'C'. Can you explain this answer?.
Two 220 V, 100 W bulbs are connected first in series and then in parallel. Each time the combination is connected to 220 V ac supply line. The power drawn by the combination in each case respectively will bea)100 W, 50 Wb)200 W,150 Wc)50 W,200 Wd)50 W,100 WCorrect answer is option 'C'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Two 220 V, 100 W bulbs are connected first in series and then in parallel. Each time the combination is connected to 220 V ac supply line. The power drawn by the combination in each case respectively will bea)100 W, 50 Wb)200 W,150 Wc)50 W,200 Wd)50 W,100 WCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two 220 V, 100 W bulbs are connected first in series and then in parallel. Each time the combination is connected to 220 V ac supply line. The power drawn by the combination in each case respectively will bea)100 W, 50 Wb)200 W,150 Wc)50 W,200 Wd)50 W,100 WCorrect answer is option 'C'. Can you explain this answer?.
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Two 220 V, 100 W bulbs are connected first in series and then in parallel. Each time the combination is connected to 220 V ac supply line. The power drawn by the combination in each case respectively will bea)100 W, 50 Wb)200 W,150 Wc)50 W,200 Wd)50 W,100 WCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for Two 220 V, 100 W bulbs are connected first in series and then in parallel. Each time the combination is connected to 220 V ac supply line. The power drawn by the combination in each case respectively will bea)100 W, 50 Wb)200 W,150 Wc)50 W,200 Wd)50 W,100 WCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of Two 220 V, 100 W bulbs are connected first in series and then in parallel. Each time the combination is connected to 220 V ac supply line. The power drawn by the combination in each case respectively will bea)100 W, 50 Wb)200 W,150 Wc)50 W,200 Wd)50 W,100 WCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
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