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Two resistors of resistances R1=100_ 3ohm and R2=200_ 4ohm are connected (a)in series,(b) in parallel.Find the equivalent resistance of the (a) series combination,(b) parallel combination.Use for (a) the relation R=R1+R2 and for (b) 1/R' = 1/R1+ 1/R2 and ∆R'/R'^2 =∆R1/R1^2+ ∆R2/R2^2. Can anyone please explain this? if anyone didn't understand u can refer NCERT P.S +1 part-1 pg.no 27 ( example 2.10 )? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared
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the NEET exam syllabus. Information about Two resistors of resistances R1=100_ 3ohm and R2=200_ 4ohm are connected (a)in series,(b) in parallel.Find the equivalent resistance of the (a) series combination,(b) parallel combination.Use for (a) the relation R=R1+R2 and for (b) 1/R' = 1/R1+ 1/R2 and ∆R'/R'^2 =∆R1/R1^2+ ∆R2/R2^2. Can anyone please explain this? if anyone didn't understand u can refer NCERT P.S +1 part-1 pg.no 27 ( example 2.10 )? covers all topics & solutions for NEET 2024 Exam.
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Here you can find the meaning of Two resistors of resistances R1=100_ 3ohm and R2=200_ 4ohm are connected (a)in series,(b) in parallel.Find the equivalent resistance of the (a) series combination,(b) parallel combination.Use for (a) the relation R=R1+R2 and for (b) 1/R' = 1/R1+ 1/R2 and ∆R'/R'^2 =∆R1/R1^2+ ∆R2/R2^2. Can anyone please explain this? if anyone didn't understand u can refer NCERT P.S +1 part-1 pg.no 27 ( example 2.10 )? defined & explained in the simplest way possible. Besides giving the explanation of
Two resistors of resistances R1=100_ 3ohm and R2=200_ 4ohm are connected (a)in series,(b) in parallel.Find the equivalent resistance of the (a) series combination,(b) parallel combination.Use for (a) the relation R=R1+R2 and for (b) 1/R' = 1/R1+ 1/R2 and ∆R'/R'^2 =∆R1/R1^2+ ∆R2/R2^2. Can anyone please explain this? if anyone didn't understand u can refer NCERT P.S +1 part-1 pg.no 27 ( example 2.10 )?, a detailed solution for Two resistors of resistances R1=100_ 3ohm and R2=200_ 4ohm are connected (a)in series,(b) in parallel.Find the equivalent resistance of the (a) series combination,(b) parallel combination.Use for (a) the relation R=R1+R2 and for (b) 1/R' = 1/R1+ 1/R2 and ∆R'/R'^2 =∆R1/R1^2+ ∆R2/R2^2. Can anyone please explain this? if anyone didn't understand u can refer NCERT P.S +1 part-1 pg.no 27 ( example 2.10 )? has been provided alongside types of Two resistors of resistances R1=100_ 3ohm and R2=200_ 4ohm are connected (a)in series,(b) in parallel.Find the equivalent resistance of the (a) series combination,(b) parallel combination.Use for (a) the relation R=R1+R2 and for (b) 1/R' = 1/R1+ 1/R2 and ∆R'/R'^2 =∆R1/R1^2+ ∆R2/R2^2. Can anyone please explain this? if anyone didn't understand u can refer NCERT P.S +1 part-1 pg.no 27 ( example 2.10 )? theory, EduRev gives you an
ample number of questions to practice Two resistors of resistances R1=100_ 3ohm and R2=200_ 4ohm are connected (a)in series,(b) in parallel.Find the equivalent resistance of the (a) series combination,(b) parallel combination.Use for (a) the relation R=R1+R2 and for (b) 1/R' = 1/R1+ 1/R2 and ∆R'/R'^2 =∆R1/R1^2+ ∆R2/R2^2. Can anyone please explain this? if anyone didn't understand u can refer NCERT P.S +1 part-1 pg.no 27 ( example 2.10 )? tests, examples and also practice NEET tests.