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for two resistors R1 and R2 connected in parallel find the relative error in their equivalent resistance if R1 =( 50 +- 2 )ohm and R 2 = (100+-3)ohm
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for two resistors R1 and R2 connected in parallel find the relative er...
Two resistors (R1 & R2) are connected in parallel. As,1/re = 1/r1 + 1/r2Then re = r1r2/r1+r2Putting values:=50x100/50+100=5000/160=100/3 (Ans)Now, Parallel Connection error:R(error) = R1^2 dB +R2^2dA/ (R1+R2)^2 =50x50 (3)+100x100 (2)/150x150 =7500+20000/150x150 =11/9 (Ans)Relative Error = R(error)/re =(11/9)/100/3 =0.03666 (Ans)
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Most Upvoted Answer
for two resistors R1 and R2 connected in parallel find the relative er...
Equivalent resistance for parallel combination is__
R = R1*R2/ ( R1+ R 2).........
R = 50 * 100 / ( 50 + 100 )
= 5000/ 150
= 500 / 15 .........
Relative error is
dR/R^2 = dR1 / R1^2 + dR2 / R2^2.........
dR/ R^2= 2 / 50^2 + 3 / 100^2 ............
dR/ R^2 = 2 / 2500 + 3 / 10000
= 8 / 10000 + 3 / 10000
= 11 / 10000 ..................
[ dR/ R= 11 * 10^-2 ohm = 00.11ohm ] ( relative error)
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for two resistors R1 and R2 connected in parallel find the relative er...
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for two resistors R1 and R2 connected in parallel find the relative error in their equivalent resistance if R1 =( 50 +- 2 )ohm and R 2 = (100+-3)ohm
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