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A linear harmonic oscillator of force constant 2 × 106 N/m and amplitude 0.01 m has a total mechanical energy of 160 J. Its [1996]
  • a)
    maximum potential energy is 160 J
  • b)
    maximum potential energy is 100 J
  • c)
    minimum potential energy is zero
  • d)
    minimum potential energy is 100 J
Correct answer is option 'A,B'. Can you explain this answer?
Verified Answer
A linear harmonic oscillator of force constant 2 × 106 N/m and a...
(a, b) k = 2 × 106 N/m
Amplitude (A) = 0.01 m
Total mechanical energy = 160J
As we know that total mechanical energy is equal to total maximum potential energy.
Maximum K. E.
This question is part of UPSC exam. View all NEET courses
Most Upvoted Answer
A linear harmonic oscillator of force constant 2 × 106 N/m and a...
A
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A linear harmonic oscillator of force constant 2 × 106 N/m and amplitude 0.01 m has a total mechanical energy of 160 J. Its [1996]a)maximum potential energy is 160 Jb)maximum potential energy is 100 Jc)minimum potential energy is zerod)minimum potential energy is 100 JCorrect answer is option 'A,B'. Can you explain this answer?
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