Identifying the Compound without Multiple Bonds
To determine which of the given compounds lacks multiple bonds, we need to analyze their structures.
1. CH3CN (Acetonitrile)
- Contains a triple bond between carbon and nitrogen (C≡N).
- Therefore, it has a multiple bond.
2. HCOOH (Formic Acid)
- Contains a double bond between carbon and oxygen (C=O).
- Thus, it includes a multiple bond.
3. CH2N2 (Diazomethane)
- Contains a double bond between carbon and nitrogen (C=N) and a nitrogen-nitrogen double bond (N=N).
- Hence, it has multiple bonds.
4. C3H6 (Propene)
- Contains a double bond between two carbon atoms (C=C).
- This compound also exhibits a multiple bond.
Conclusion
After analyzing each compound, it's evident that all options contain multiple bonds except for one.
Final Answer
- None of the compounds listed are devoid of multiple bonds. However, the question seems to imply looking for the simplest structure, which could lead to further investigation into the nature of the bonds present.
In summary, all provided compounds contain at least one multiple bond, thus none of them is completely free of multiple bonding.