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The sum of the ages of a father and his son is 100 yrs now. Five years ago their ages were in the ratio 2 : 1. Find the ratio of ages of father and son after 10 years.
- a)4 : 3
- b)5 : 3
- c)3 : 5
- d)10 : 7
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
The sum of the ages of a father and his son is 100 yrs now. Five years...
The correct option is B.
Let present age of father - x
present age of son. - y
X + Y = 100. y = 100 - x
five years ago their ages = x -5/y-5 =2/1
- x - 5 = 2y - 10 , x - 5 = (100-x)2 - 10
x - 5 = 200 - 2x - 10 , 3x = 195 ,
x = 195/3 = 65,
y = 100 - 65 = 35
Ratio after 10 years= 65+10/35+10 = 75/45 =5/3.
Let present age of father - x
present age of son. - y
X + Y = 100. y = 100 - x
five years ago their ages = x -5/y-5 =2/1
- x - 5 = 2y - 10 , x - 5 = (100-x)2 - 10
x - 5 = 200 - 2x - 10 , 3x = 195 ,
x = 195/3 = 65,
y = 100 - 65 = 35
Ratio after 10 years= 65+10/35+10 = 75/45 =5/3.
Most Upvoted Answer
The sum of the ages of a father and his son is 100 yrs now. Five years...
Let present age of father - x
present age of son. - y
X + Y = 100. y = 100 - x
five years ago their ages = x -5/y-5 =2/1
- x - 5 = 2y - 10 , x - 5 = (100-x)2 - 10
x - 5 = 200 - 2x - 10 , 3x = 195 ,
x = 195/3 = 65,
y = 100 - 65 = 35
Ratio after 10 years= 65+10/35+10 = 75/45 =5/3.
present age of son. - y
X + Y = 100. y = 100 - x
five years ago their ages = x -5/y-5 =2/1
- x - 5 = 2y - 10 , x - 5 = (100-x)2 - 10
x - 5 = 200 - 2x - 10 , 3x = 195 ,
x = 195/3 = 65,
y = 100 - 65 = 35
Ratio after 10 years= 65+10/35+10 = 75/45 =5/3.
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Community Answer
The sum of the ages of a father and his son is 100 yrs now. Five years...
Given:
- Sum of ages of father and son = 100
- 5 years ago, their ages were in the ratio 2:1
To find:
- Ratio of ages of father and son after 10 years
Solution:
Let the present age of the son be x.
Then, the present age of the father = 100 - x.
5 years ago, their ages were (x - 5) and (100 - x - 5) = (95 - x) and the ratio was 2:1.
So, (95 - x)/(x - 5) = 2/1
Solving this equation, we get x = 25.
So, the present age of the son = x = 25 and the present age of the father = 100 - x = 75.
After 10 years,
- Age of son = 25 + 10 = 35
- Age of father = 75 + 10 = 85
Therefore, the ratio of ages of father and son after 10 years = 85/35 = 17/7 = 5/3
Hence, the correct option is (B) 5:3.
- Sum of ages of father and son = 100
- 5 years ago, their ages were in the ratio 2:1
To find:
- Ratio of ages of father and son after 10 years
Solution:
Let the present age of the son be x.
Then, the present age of the father = 100 - x.
5 years ago, their ages were (x - 5) and (100 - x - 5) = (95 - x) and the ratio was 2:1.
So, (95 - x)/(x - 5) = 2/1
Solving this equation, we get x = 25.
So, the present age of the son = x = 25 and the present age of the father = 100 - x = 75.
After 10 years,
- Age of son = 25 + 10 = 35
- Age of father = 75 + 10 = 85
Therefore, the ratio of ages of father and son after 10 years = 85/35 = 17/7 = 5/3
Hence, the correct option is (B) 5:3.
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