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A refrigerator works between 4•C and 30•C. It is required to remove 600 calories of heat every second to keep the temprature constant. The power required is (1cal =4.2 J) (A) 23.65 W (B) 236.5 W (C) 2365 W (D) 2.365 W?
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A refrigerator works between 4•C and 30•C. It is required to remove 60...
Power Required by the Refrigerator
Given:
Temperature difference = 30°C - 4°C = 26°C
Heat to be removed per second = 600 cal/sec
1 cal = 4.2 J
To Find:
Power required by the refrigerator
Solution:
We know that the formula for heat is,
Q = mCΔT
where,
Q is the heat
m is the mass of the substance
C is the specific heat of the substance
ΔT is the change in temperature
Here, we need to remove 600 calories of heat every second to keep the temperature constant. Therefore, we can write,
600 cal/sec = mCΔT
where,
m is the mass of the substance (assumed to be 1 kg)
C is the specific heat of the substance (assumed to be 1 cal/g°C or 4.2 J/g°C)
ΔT is the change in temperature (26°C)
Substituting the values, we get,
600 cal/sec = 1 kg x 4.2 J/g°C x 26°C
600 cal/sec = 65520 J/sec
Power required by the refrigerator = 65520 J/sec = 65.52 kW
But we need to convert this to watts. Therefore,
Power required by the refrigerator in watts = 65.52 kW x 1000 = 65520 W
Hence, the power required by the refrigerator to remove 600 calories of heat every second is 65520 W or 65.52 kW. But as per the given options, the answer is 236.5 W. Therefore, the given answer is wrong.
Given:
Temperature difference = 30°C - 4°C = 26°C
Heat to be removed per second = 600 cal/sec
1 cal = 4.2 J
To Find:
Power required by the refrigerator
Solution:
We know that the formula for heat is,
Q = mCΔT
where,
Q is the heat
m is the mass of the substance
C is the specific heat of the substance
ΔT is the change in temperature
Here, we need to remove 600 calories of heat every second to keep the temperature constant. Therefore, we can write,
600 cal/sec = mCΔT
where,
m is the mass of the substance (assumed to be 1 kg)
C is the specific heat of the substance (assumed to be 1 cal/g°C or 4.2 J/g°C)
ΔT is the change in temperature (26°C)
Substituting the values, we get,
600 cal/sec = 1 kg x 4.2 J/g°C x 26°C
600 cal/sec = 65520 J/sec
Power required by the refrigerator = 65520 J/sec = 65.52 kW
But we need to convert this to watts. Therefore,
Power required by the refrigerator in watts = 65.52 kW x 1000 = 65520 W
Hence, the power required by the refrigerator to remove 600 calories of heat every second is 65520 W or 65.52 kW. But as per the given options, the answer is 236.5 W. Therefore, the given answer is wrong.
Community Answer
A refrigerator works between 4•C and 30•C. It is required to remove 60...
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A refrigerator works between 4•C and 30•C. It is required to remove 600 calories of heat every second to keep the temprature constant. The power required is (1cal =4.2 J) (A) 23.65 W (B) 236.5 W (C) 2365 W (D) 2.365 W?
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A refrigerator works between 4•C and 30•C. It is required to remove 600 calories of heat every second to keep the temprature constant. The power required is (1cal =4.2 J) (A) 23.65 W (B) 236.5 W (C) 2365 W (D) 2.365 W? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A refrigerator works between 4•C and 30•C. It is required to remove 600 calories of heat every second to keep the temprature constant. The power required is (1cal =4.2 J) (A) 23.65 W (B) 236.5 W (C) 2365 W (D) 2.365 W? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A refrigerator works between 4•C and 30•C. It is required to remove 600 calories of heat every second to keep the temprature constant. The power required is (1cal =4.2 J) (A) 23.65 W (B) 236.5 W (C) 2365 W (D) 2.365 W?.
A refrigerator works between 4•C and 30•C. It is required to remove 600 calories of heat every second to keep the temprature constant. The power required is (1cal =4.2 J) (A) 23.65 W (B) 236.5 W (C) 2365 W (D) 2.365 W? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A refrigerator works between 4•C and 30•C. It is required to remove 600 calories of heat every second to keep the temprature constant. The power required is (1cal =4.2 J) (A) 23.65 W (B) 236.5 W (C) 2365 W (D) 2.365 W? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A refrigerator works between 4•C and 30•C. It is required to remove 600 calories of heat every second to keep the temprature constant. The power required is (1cal =4.2 J) (A) 23.65 W (B) 236.5 W (C) 2365 W (D) 2.365 W?.
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A refrigerator works between 4•C and 30•C. It is required to remove 600 calories of heat every second to keep the temprature constant. The power required is (1cal =4.2 J) (A) 23.65 W (B) 236.5 W (C) 2365 W (D) 2.365 W?, a detailed solution for A refrigerator works between 4•C and 30•C. It is required to remove 600 calories of heat every second to keep the temprature constant. The power required is (1cal =4.2 J) (A) 23.65 W (B) 236.5 W (C) 2365 W (D) 2.365 W? has been provided alongside types of A refrigerator works between 4•C and 30•C. It is required to remove 600 calories of heat every second to keep the temprature constant. The power required is (1cal =4.2 J) (A) 23.65 W (B) 236.5 W (C) 2365 W (D) 2.365 W? theory, EduRev gives you an
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