A refrigerator works between 4•C and 30•C. It is required to remove 60...
Power Required by the Refrigerator
Given:
Temperature difference = 30°C - 4°C = 26°C
Heat to be removed per second = 600 cal/sec
1 cal = 4.2 J
To Find:
Power required by the refrigerator
Solution:
We know that the formula for heat is,
Q = mCΔT
where,
Q is the heat
m is the mass of the substance
C is the specific heat of the substance
ΔT is the change in temperature
Here, we need to remove 600 calories of heat every second to keep the temperature constant. Therefore, we can write,
600 cal/sec = mCΔT
where,
m is the mass of the substance (assumed to be 1 kg)
C is the specific heat of the substance (assumed to be 1 cal/g°C or 4.2 J/g°C)
ΔT is the change in temperature (26°C)
Substituting the values, we get,
600 cal/sec = 1 kg x 4.2 J/g°C x 26°C
600 cal/sec = 65520 J/sec
Power required by the refrigerator = 65520 J/sec = 65.52 kW
But we need to convert this to watts. Therefore,
Power required by the refrigerator in watts = 65.52 kW x 1000 = 65520 W
Hence, the power required by the refrigerator to remove 600 calories of heat every second is 65520 W or 65.52 kW. But as per the given options, the answer is 236.5 W. Therefore, the given answer is wrong.
A refrigerator works between 4•C and 30•C. It is required to remove 60...
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