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A balloon rises from rest with a constant acceleration 9/8. A stone is released from it when it has risen to height h. The time taken by stone to reach the ground is?
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A balloon rises from rest with a constant acceleration 9/8. A stone is...
The Problem:

A balloon is rising from rest with a constant acceleration of 9/8. At a certain height h, a stone is released from the balloon. We need to find the time taken by the stone to reach the ground.

Solution:

To solve this problem, we can break it down into two parts: the motion of the balloon and the motion of the stone.

Motion of the Balloon:

Let's consider the motion of the balloon first. We are given that the balloon is rising from rest with a constant acceleration of 9/8. This means that its velocity is increasing at a rate of 9/8 m/s^2.

We can use the kinematic equation v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time taken. Since the balloon starts from rest, its initial velocity u is 0.

Using the equation, we can find the time taken by the balloon to reach height h. Let's denote this time as T.

v = u + at
0 + (9/8)T = T * (9/8)
0 = 0

This shows that the balloon reaches height h in no time, which means that the stone is released instantaneously.

Motion of the Stone:

Once the stone is released from the balloon, it starts falling downwards under the influence of gravity. The stone experiences a constant acceleration of -9.8 m/s^2 (negative because it is in the opposite direction to the motion of the balloon).

We can use the kinematic equation s = ut + (1/2)at^2, where s is the distance traveled, u is the initial velocity, a is the acceleration, and t is the time taken. Since the stone starts from rest, its initial velocity u is 0.

We need to find the time taken by the stone to reach the ground, which is the distance traveled by the stone from height h to the ground.

s = ut + (1/2)at^2
s = 0 + (1/2)(-9.8)t^2
h = -4.9t^2
t^2 = -h/4.9
t = sqrt(-h/4.9)

Conclusion:

The time taken by the stone to reach the ground is sqrt(-h/4.9). However, it's important to note that the value of h cannot be negative. If h is positive, the stone will take the square root of a positive number, resulting in a real positive value for the time taken. If h is zero, the stone will take zero time to reach the ground.
Community Answer
A balloon rises from rest with a constant acceleration 9/8. A stone is...
Answer may be nearly equal to 1.4√h seconds.
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A balloon rises from rest with a constant acceleration 9/8. A stone is released from it when it has risen to height h. The time taken by stone to reach the ground is?
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A balloon rises from rest with a constant acceleration 9/8. A stone is released from it when it has risen to height h. The time taken by stone to reach the ground is? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A balloon rises from rest with a constant acceleration 9/8. A stone is released from it when it has risen to height h. The time taken by stone to reach the ground is? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A balloon rises from rest with a constant acceleration 9/8. A stone is released from it when it has risen to height h. The time taken by stone to reach the ground is?.
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