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A bomb of mass 1kg thrown vertically upwards with a speed u = 100 m per second explodes into two parts after time equals to 5 seconds a fragment of mass m 400 gm move downwards with a speed V 1 = 25 m per second then speed v2 is?
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A bomb of mass 1kg thrown vertically upwards with a speed u = 100 m pe...
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A bomb of mass 1kg thrown vertically upwards with a speed u = 100 m pe...
Answer:
Given:
Mass of bomb, m = 1 kg
Initial velocity of bomb, u = 100 m/s
Mass of fragment, m1 = 400 g = 0.4 kg
Time taken for explosion, t = 5 s
Velocity of fragment moving downwards, V1 = 25 m/s
Calculations:
The initial momentum of the bomb before explosion can be calculated as:
p = m * u
p = 1 kg * 100 m/s
p = 100 kg m/s
After the explosion, the momentum is conserved, so the total momentum is split between the two fragments. Let the velocity of the second fragment be V2.
The momentum of the first fragment moving downwards is:
p1 = m1 * V1
p1 = 0.4 kg * 25 m/s
p1 = 10 kg m/s
The momentum of the second fragment moving upwards is:
p2 = (m - m1) * V2
p2 = (1 kg - 0.4 kg) * V2
p2 = 0.6 kg * V2
The total momentum of the fragments is:
p_total = p1 + p2
p_total = 10 kg m/s + 0.6 kg * V2
Since momentum is conserved:
p_total = p
100 kg m/s = 10 kg m/s + 0.6 kg * V2
Solving for V2, we get:
V2 = (100 kg m/s - 10 kg m/s) / 0.6 kg
V2 = 150 m/s
Answer: Therefore, the speed of the second fragment is 150 m/s.
Given:
Mass of bomb, m = 1 kg
Initial velocity of bomb, u = 100 m/s
Mass of fragment, m1 = 400 g = 0.4 kg
Time taken for explosion, t = 5 s
Velocity of fragment moving downwards, V1 = 25 m/s
Calculations:
The initial momentum of the bomb before explosion can be calculated as:
p = m * u
p = 1 kg * 100 m/s
p = 100 kg m/s
After the explosion, the momentum is conserved, so the total momentum is split between the two fragments. Let the velocity of the second fragment be V2.
The momentum of the first fragment moving downwards is:
p1 = m1 * V1
p1 = 0.4 kg * 25 m/s
p1 = 10 kg m/s
The momentum of the second fragment moving upwards is:
p2 = (m - m1) * V2
p2 = (1 kg - 0.4 kg) * V2
p2 = 0.6 kg * V2
The total momentum of the fragments is:
p_total = p1 + p2
p_total = 10 kg m/s + 0.6 kg * V2
Since momentum is conserved:
p_total = p
100 kg m/s = 10 kg m/s + 0.6 kg * V2
Solving for V2, we get:
V2 = (100 kg m/s - 10 kg m/s) / 0.6 kg
V2 = 150 m/s
Answer: Therefore, the speed of the second fragment is 150 m/s.
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A bomb of mass 1kg thrown vertically upwards with a speed u = 100 m per second explodes into two parts after time equals to 5 seconds a fragment of mass m 400 gm move downwards with a speed V 1 = 25 m per second then speed v2 is?
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A bomb of mass 1kg thrown vertically upwards with a speed u = 100 m per second explodes into two parts after time equals to 5 seconds a fragment of mass m 400 gm move downwards with a speed V 1 = 25 m per second then speed v2 is? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A bomb of mass 1kg thrown vertically upwards with a speed u = 100 m per second explodes into two parts after time equals to 5 seconds a fragment of mass m 400 gm move downwards with a speed V 1 = 25 m per second then speed v2 is? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bomb of mass 1kg thrown vertically upwards with a speed u = 100 m per second explodes into two parts after time equals to 5 seconds a fragment of mass m 400 gm move downwards with a speed V 1 = 25 m per second then speed v2 is?.
A bomb of mass 1kg thrown vertically upwards with a speed u = 100 m per second explodes into two parts after time equals to 5 seconds a fragment of mass m 400 gm move downwards with a speed V 1 = 25 m per second then speed v2 is? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A bomb of mass 1kg thrown vertically upwards with a speed u = 100 m per second explodes into two parts after time equals to 5 seconds a fragment of mass m 400 gm move downwards with a speed V 1 = 25 m per second then speed v2 is? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bomb of mass 1kg thrown vertically upwards with a speed u = 100 m per second explodes into two parts after time equals to 5 seconds a fragment of mass m 400 gm move downwards with a speed V 1 = 25 m per second then speed v2 is?.
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