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Someone solve attached question?
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Someone solve attached question?
[Cr(H20)4Cl2]Cl=>[Cr(H20)4Cl2](+1) + Cl(-1)
no. of ionisable ion in complex is 1 which is Cl
Molarity = number of mole of solute/volume of solution {in L}
Number of moles of solute = 0.01 × 0.1 = 0.001 mol
hence no of moles of Cl(-)= 1×0.001=0.001
and Cl combines with Ag to form AgCl
so moles of AgCl formed =0.001
no. of ionisable ion in complex is 1 which is Cl
Molarity = number of mole of solute/volume of solution {in L}
Number of moles of solute = 0.01 × 0.1 = 0.001 mol
hence no of moles of Cl(-)= 1×0.001=0.001
and Cl combines with Ag to form AgCl
so moles of AgCl formed =0.001
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Someone solve attached question?
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