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A source of sound gives 5 beats per second, when sounded with another source of frequency 100/sec. The second harmonic of the source, together with a source of frequency 205/sec gives 5 beats per second. What is the frequency of the source? [1995]
  • a)
    95 sec–1
  • b)
    100 sec–1
  • c)
    105 sec–1
  • d)
    205 sec–1
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A source of sound gives 5 beats per second, when sounded with another ...
Frequency of first source with 5 beats/ sec = 100 Hz and frequency of second source with 5 beats/sec = 205 Hz. The frequency of the first source = 100 ± 5 = 105 or 95 Hz. Therefore, frequency of second harmonic of source = 210 Hz or 190 Hz. As the second harmonic gives 5 beats/ second with the sound of frequency 205 Hz, therefore, frequency of second harmonic source should be 210 Hz or frequency of source = 105 Hz.
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A source of sound gives 5 beats per second, when sounded with another ...
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Community Answer
A source of sound gives 5 beats per second, when sounded with another ...
Let's call the frequency of the source we are trying to find "f".

Given that the source gives 5 beats per second when sounded with another source of frequency 100/sec, we can set up the equation:

f - 100 = 5

Simplifying this equation, we get:

f = 105

Now, let's consider the second harmonic of the source. The second harmonic has a frequency that is twice the frequency of the source, so it would be 2f.

Given that the second harmonic (2f) together with a source of frequency 205/sec gives 5 beats per second, we can set up the equation:

2f - 205 = 5

Simplifying this equation, we get:

2f = 210
f = 105

Therefore, the frequency of the source is 105/sec.
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A source of sound gives 5 beats per second, when sounded with another source of frequency 100/sec. The second harmonic of the source, together with a source of frequency 205/sec gives 5 beats per second. What is the frequency of the source? [1995]a)95 sec–1b)100 sec–1c)105 sec–1d)205 sec–1Correct answer is option 'C'. Can you explain this answer?
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