water(Cp=4180J/kgoC)enter into the 2.5 cm internal diameter tube of a ...
Problem:
Water (Cp=4180J/kgoC) enters into the 2.5 cm internal diameter tube of a double pipe counter flow heat exchanger at 17oC at a rate of 3kg/s. Water is heated by steam condensing at 120oC (hfg= 2203kj/kg) in the shell. If the overall heat transfer coefficient of the heat exchanger is 900W/m2oC, determine the length of the tube required in order to heat the water to 80oC using LMTD and NTU method?
Solution:
Step 1: Determine the LMTD
LMTD (Logarithmic Mean Temperature Difference) is determined using the formula:
LMTD = (ΔT1 - ΔT2) / ln(ΔT1 / ΔT2)
where ΔT1 = T1,in - T2,out and ΔT2 = T1,out - T2,in
Given:
- T1,in = 17oC
- T1,out = 80oC
- T2,in = 120oC
- T2,out = ? (unknown)
Using the formula to calculate ΔT1 and ΔT2:
- ΔT1 = 17 - T2,out
- ΔT2 = 120 - 80 = 40
Substituting the values in the LMTD formula:
LMTD = (17 - T2,out - 40) / ln((17 - T2,out) / 40)
LMTD = (57 - T2,out) / ln((17 - T2,out) / 40)
Step 2: Determine the NTU
NTU (Number of Transfer Units) is determined using the formula:
NTU = UA / Cp_min
where U is the overall heat transfer coefficient, A is the heat transfer area, and Cp_min is the minimum heat capacity.
Given:
- U = 900 W/m2oC
- A = πDL (where D is the inner diameter of the tube and L is the length of the tube)
- Cp_min = 4180 J/kgoC (for water)
Substituting the values in the NTU formula:
NTU = (900 x π x 0.025 x L) / 4180
NTU = 0.017 x L
Step 3: Determine the Effectiveness
Effectiveness is determined using the formula:
ε = (1 - e^(-NTU(1 - C))) / (1 - C x e^(-NTU(1 - C)))
where C = (Cp_min,C / Cp_max,F) and Cp_max,F is the