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If the energy in the first excited state in hydrogen atom is 23.8 ev then the potential energy of a hydrogen atom in the ground state can be assumed to be?
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If the energy in the first excited state in hydrogen atom is 23.8 ev t...
E=-13.6(Z/n)^2
E~1/n^2
first excited state means n=2 and ground state n=1
E1/E2=(n2/n1)^2
E1=23.8×4
= -95.2ev
now E=PE/2
PE=E×2
= -190.4 ev
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If the energy in the first excited state in hydrogen atom is 23.8 ev then the potential energy of a hydrogen atom in the ground state can be assumed to be?
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