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A transformer of 100% efficiency has 200 turns in the primary coil and 40000 rums in secondary coil. It is connected to a 220 V main supply and secondary feeds to a 100 kfl resistance. The potential difference per turn is
- a)1.1 V
- b)25 V
- c)18 V
- d)11 V
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
A transformer of 100% efficiency has 200 turns in the primary coil and...
Potential difference per turn is given by the formula:
Vp = Vs/Ns
Where:
Vp = potential difference per turn in the primary coil
Vs = potential difference across the secondary coil
Ns = number of turns in the secondary coil
Given data:
Number of turns in the primary coil (Np) = 200
Number of turns in the secondary coil (Ns) = 40000
Potential difference across the secondary coil (Vs) = 220 V
Resistance in the secondary coil (Rs) = 100 kΩ = 100000 Ω
Let's calculate the potential difference per turn:
Step 1: Calculate the current flowing through the secondary coil using Ohm's law.
Is = Vs / Rs
= 220 V / 100000 Ω
= 0.0022 A
Step 2: Calculate the current flowing through the primary coil using the transformer equation.
Is / Ip = Ns / Np
Ip = (Ns / Np) * Is
= (40000 / 200) * 0.0022 A
= 0.44 A
Step 3: Calculate the potential difference per turn in the primary coil.
Vp = Ip * Rp
= 0.44 A * 220 V
= 96.8 V
Since we have 200 turns in the primary coil, the potential difference per turn is:
Vp / Np = 96.8 V / 200
= 0.484 V
Therefore, the potential difference per turn in the primary coil is approximately 0.484 V. None of the given options match this value, so the correct answer is not provided in the options given.
Note: The given answer in option 'A' is incorrect.
Vp = Vs/Ns
Where:
Vp = potential difference per turn in the primary coil
Vs = potential difference across the secondary coil
Ns = number of turns in the secondary coil
Given data:
Number of turns in the primary coil (Np) = 200
Number of turns in the secondary coil (Ns) = 40000
Potential difference across the secondary coil (Vs) = 220 V
Resistance in the secondary coil (Rs) = 100 kΩ = 100000 Ω
Let's calculate the potential difference per turn:
Step 1: Calculate the current flowing through the secondary coil using Ohm's law.
Is = Vs / Rs
= 220 V / 100000 Ω
= 0.0022 A
Step 2: Calculate the current flowing through the primary coil using the transformer equation.
Is / Ip = Ns / Np
Ip = (Ns / Np) * Is
= (40000 / 200) * 0.0022 A
= 0.44 A
Step 3: Calculate the potential difference per turn in the primary coil.
Vp = Ip * Rp
= 0.44 A * 220 V
= 96.8 V
Since we have 200 turns in the primary coil, the potential difference per turn is:
Vp / Np = 96.8 V / 200
= 0.484 V
Therefore, the potential difference per turn in the primary coil is approximately 0.484 V. None of the given options match this value, so the correct answer is not provided in the options given.
Note: The given answer in option 'A' is incorrect.
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A transformer of 100% efficiency has 200 turns in the primary coil and...
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A transformer of 100% efficiency has 200 turns in the primary coil and 40000 rums in secondary coil. It is connected to a 220 V main supply and secondary feeds to a 100 kfl resistance. The potential difference per turn isa)1.1 Vb)25 Vc)18 Vd)11 VCorrect answer is option 'A'. Can you explain this answer?
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