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3.92 g of ferrous ammonium sulphate crystals are dissolved in 100 ml of water, 20 ml of this solution requires 18 ml of KMnO4 present in one litre of the solution is (a) 3.476 g (c) 34.76 g (b) 12.38 g (d)1.256?
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Given:
- Mass of ferrous ammonium sulphate (Fe(NH4)2(SO4)2): 3.92 g
- Volume of water used for dissolution: 100 ml
- Volume of KMnO4 solution required for titration: 18 ml
- Concentration of KMnO4 solution: 1 L
To find:
- Mass of ferrous ammonium sulphate in 1 L of solution
Solution:
Step 1: Calculate the molarity of the KMnO4 solution
- The volume of the KMnO4 solution used for titration is 18 ml.
- The concentration of the KMnO4 solution is given as 1 L.
- Therefore, the molarity of the KMnO4 solution can be calculated using the formula:
Molarity (M) = (Number of moles of solute) / (Volume of solution in liters)
Step 2: Calculate the number of moles of KMnO4
- From the balanced chemical equation of the reaction between KMnO4 and Fe(NH4)2(SO4)2, we can see that the stoichiometric ratio is 5:1. This means that 5 moles of KMnO4 react with 1 mole of Fe(NH4)2(SO4)2.
- We can use this ratio to calculate the number of moles of KMnO4 using the formula:
Moles of KMnO4 = Molarity of KMnO4 solution * Volume of KMnO4 solution used in liters
Step 3: Calculate the number of moles of Fe(NH4)2(SO4)2
- From the stoichiometric ratio mentioned earlier, we know that 1 mole of Fe(NH4)2(SO4)2 reacts with 5 moles of KMnO4.
- Therefore, the number of moles of Fe(NH4)2(SO4)2 can be calculated using the formula:
Moles of Fe(NH4)2(SO4)2 = (Moles of KMnO4) / 5
Step 4: Calculate the mass of Fe(NH4)2(SO4)2 in 1 L of solution
- The mass of Fe(NH4)2(SO4)2 used in the solution is given as 3.92 g.
- The volume of water used for dissolution is 100 ml, which is equal to 0.1 L.
- Therefore, the mass of Fe(NH4)2(SO4)2 in 1 L of solution can be calculated using the formula:
Mass of Fe(NH4)2(SO4)2 = (Moles of Fe(NH4)2(SO4)2) * (Molar mass of Fe(NH4)2(SO4)2)
Step 5: Calculate the final answer
- Plug in the values calculated in the previous steps to find the mass of Fe(NH4)2(SO4)2 in 1 L of solution.
Answer:
The mass of ferrous ammonium sulphate (Fe(NH4)
- Mass of ferrous ammonium sulphate (Fe(NH4)2(SO4)2): 3.92 g
- Volume of water used for dissolution: 100 ml
- Volume of KMnO4 solution required for titration: 18 ml
- Concentration of KMnO4 solution: 1 L
To find:
- Mass of ferrous ammonium sulphate in 1 L of solution
Solution:
Step 1: Calculate the molarity of the KMnO4 solution
- The volume of the KMnO4 solution used for titration is 18 ml.
- The concentration of the KMnO4 solution is given as 1 L.
- Therefore, the molarity of the KMnO4 solution can be calculated using the formula:
Molarity (M) = (Number of moles of solute) / (Volume of solution in liters)
Step 2: Calculate the number of moles of KMnO4
- From the balanced chemical equation of the reaction between KMnO4 and Fe(NH4)2(SO4)2, we can see that the stoichiometric ratio is 5:1. This means that 5 moles of KMnO4 react with 1 mole of Fe(NH4)2(SO4)2.
- We can use this ratio to calculate the number of moles of KMnO4 using the formula:
Moles of KMnO4 = Molarity of KMnO4 solution * Volume of KMnO4 solution used in liters
Step 3: Calculate the number of moles of Fe(NH4)2(SO4)2
- From the stoichiometric ratio mentioned earlier, we know that 1 mole of Fe(NH4)2(SO4)2 reacts with 5 moles of KMnO4.
- Therefore, the number of moles of Fe(NH4)2(SO4)2 can be calculated using the formula:
Moles of Fe(NH4)2(SO4)2 = (Moles of KMnO4) / 5
Step 4: Calculate the mass of Fe(NH4)2(SO4)2 in 1 L of solution
- The mass of Fe(NH4)2(SO4)2 used in the solution is given as 3.92 g.
- The volume of water used for dissolution is 100 ml, which is equal to 0.1 L.
- Therefore, the mass of Fe(NH4)2(SO4)2 in 1 L of solution can be calculated using the formula:
Mass of Fe(NH4)2(SO4)2 = (Moles of Fe(NH4)2(SO4)2) * (Molar mass of Fe(NH4)2(SO4)2)
Step 5: Calculate the final answer
- Plug in the values calculated in the previous steps to find the mass of Fe(NH4)2(SO4)2 in 1 L of solution.
Answer:
The mass of ferrous ammonium sulphate (Fe(NH4)
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3.92 g of ferrous ammonium sulphate crystals are dissolved in 100 ml of water, 20 ml of this solution requires 18 ml of KMnO4 present in one litre of the solution is (a) 3.476 g (c) 34.76 g (b) 12.38 g (d)1.256?
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3.92 g of ferrous ammonium sulphate crystals are dissolved in 100 ml of water, 20 ml of this solution requires 18 ml of KMnO4 present in one litre of the solution is (a) 3.476 g (c) 34.76 g (b) 12.38 g (d)1.256? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 3.92 g of ferrous ammonium sulphate crystals are dissolved in 100 ml of water, 20 ml of this solution requires 18 ml of KMnO4 present in one litre of the solution is (a) 3.476 g (c) 34.76 g (b) 12.38 g (d)1.256? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 3.92 g of ferrous ammonium sulphate crystals are dissolved in 100 ml of water, 20 ml of this solution requires 18 ml of KMnO4 present in one litre of the solution is (a) 3.476 g (c) 34.76 g (b) 12.38 g (d)1.256?.
3.92 g of ferrous ammonium sulphate crystals are dissolved in 100 ml of water, 20 ml of this solution requires 18 ml of KMnO4 present in one litre of the solution is (a) 3.476 g (c) 34.76 g (b) 12.38 g (d)1.256? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 3.92 g of ferrous ammonium sulphate crystals are dissolved in 100 ml of water, 20 ml of this solution requires 18 ml of KMnO4 present in one litre of the solution is (a) 3.476 g (c) 34.76 g (b) 12.38 g (d)1.256? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 3.92 g of ferrous ammonium sulphate crystals are dissolved in 100 ml of water, 20 ml of this solution requires 18 ml of KMnO4 present in one litre of the solution is (a) 3.476 g (c) 34.76 g (b) 12.38 g (d)1.256?.
Solutions for 3.92 g of ferrous ammonium sulphate crystals are dissolved in 100 ml of water, 20 ml of this solution requires 18 ml of KMnO4 present in one litre of the solution is (a) 3.476 g (c) 34.76 g (b) 12.38 g (d)1.256? in English & in Hindi are available as part of our courses for NEET.
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3.92 g of ferrous ammonium sulphate crystals are dissolved in 100 ml of water, 20 ml of this solution requires 18 ml of KMnO4 present in one litre of the solution is (a) 3.476 g (c) 34.76 g (b) 12.38 g (d)1.256?, a detailed solution for 3.92 g of ferrous ammonium sulphate crystals are dissolved in 100 ml of water, 20 ml of this solution requires 18 ml of KMnO4 present in one litre of the solution is (a) 3.476 g (c) 34.76 g (b) 12.38 g (d)1.256? has been provided alongside types of 3.92 g of ferrous ammonium sulphate crystals are dissolved in 100 ml of water, 20 ml of this solution requires 18 ml of KMnO4 present in one litre of the solution is (a) 3.476 g (c) 34.76 g (b) 12.38 g (d)1.256? theory, EduRev gives you an
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