Question Description
Given, enthalpy of formation of CO2(g) and CaO(s) are -94.0kJ and -152kJ respectively and the enthalpy of the reaction: CaCO3(s) = CaO(s) CO2(g) is 42 kJ. The enthalpy of formation of CaCO3(s) is A) -42 kJ B) -202 kJ C) 202 kJ D) -288 kJ? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Given, enthalpy of formation of CO2(g) and CaO(s) are -94.0kJ and -152kJ respectively and the enthalpy of the reaction: CaCO3(s) = CaO(s) CO2(g) is 42 kJ. The enthalpy of formation of CaCO3(s) is A) -42 kJ B) -202 kJ C) 202 kJ D) -288 kJ? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Given, enthalpy of formation of CO2(g) and CaO(s) are -94.0kJ and -152kJ respectively and the enthalpy of the reaction: CaCO3(s) = CaO(s) CO2(g) is 42 kJ. The enthalpy of formation of CaCO3(s) is A) -42 kJ B) -202 kJ C) 202 kJ D) -288 kJ?.

Solutions for Given, enthalpy of formation of CO2(g) and CaO(s) are -94.0kJ and -152kJ respectively and the enthalpy of the reaction: CaCO3(s) = CaO(s) CO2(g) is 42 kJ. The enthalpy of formation of CaCO3(s) is A) -42 kJ B) -202 kJ C) 202 kJ D) -288 kJ? in English & in Hindi are available as part of our courses for NEET. Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.

Here you can find the meaning of Given, enthalpy of formation of CO2(g) and CaO(s) are -94.0kJ and -152kJ respectively and the enthalpy of the reaction: CaCO3(s) = CaO(s) CO2(g) is 42 kJ. The enthalpy of formation of CaCO3(s) is A) -42 kJ B) -202 kJ C) 202 kJ D) -288 kJ? defined & explained in the simplest way possible. Besides giving the explanation of Given, enthalpy of formation of CO2(g) and CaO(s) are -94.0kJ and -152kJ respectively and the enthalpy of the reaction: CaCO3(s) = CaO(s) CO2(g) is 42 kJ. The enthalpy of formation of CaCO3(s) is A) -42 kJ B) -202 kJ C) 202 kJ D) -288 kJ?, a detailed solution for Given, enthalpy of formation of CO2(g) and CaO(s) are -94.0kJ and -152kJ respectively and the enthalpy of the reaction: CaCO3(s) = CaO(s) CO2(g) is 42 kJ. The enthalpy of formation of CaCO3(s) is A) -42 kJ B) -202 kJ C) 202 kJ D) -288 kJ? has been provided alongside types of Given, enthalpy of formation of CO2(g) and CaO(s) are -94.0kJ and -152kJ respectively and the enthalpy of the reaction: CaCO3(s) = CaO(s) CO2(g) is 42 kJ. The enthalpy of formation of CaCO3(s) is A) -42 kJ B) -202 kJ C) 202 kJ D) -288 kJ? theory, EduRev gives you an ample number of questions to practice Given, enthalpy of formation of CO2(g) and CaO(s) are -94.0kJ and -152kJ respectively and the enthalpy of the reaction: CaCO3(s) = CaO(s) CO2(g) is 42 kJ. The enthalpy of formation of CaCO3(s) is A) -42 kJ B) -202 kJ C) 202 kJ D) -288 kJ? tests, examples and also practice NEET tests.