If alpha and beta are the zeroes of the quadratic polynomial p(x)=x^2-...
Explanation:
Let p(x) be a quadratic polynomial, then the general form of the quadratic polynomial is:
p(x) = ax^2 + bx + c
where a, b, and c are the coefficients of the polynomial.
Now, let alpha and beta be the roots of the given quadratic polynomial, then we have:
p(alpha) = 0 and p(beta) = 0
Using the factor theorem, we can write:
p(x) = (x - alpha)(x - beta)
Expanding the above expression, we get:
p(x) = x^2 - (alpha + beta)x + alpha * beta
Comparing the coefficients of the above equation with the given quadratic polynomial, we get:
a = 1, b = -(alpha + beta), and c = alpha * beta
Solution:
Given quadratic polynomial is:
p(x) = x^2 - (k * 6) * 2(2k - 1)
On comparing the coefficients, we get:
a = 1, b = -(alpha + beta) = (k * 6) * 2(2k - 1), and c = alpha * beta = 0.5(alpha + beta)
As alpha + beta = 2c, we get:
alpha + beta = 2 * 0.5(alpha + beta)
alpha + beta = alpha * beta
Substituting the value of b, we get:
(k * 6) * 2(2k - 1) = -(alpha + beta)
(k * 6) * 2(2k - 1) = -alpha - beta
Solving the above equation, we get:
k = 0 or k = 5/6
Therefore, the value of k is either 0 or 5/6.