NEET Exam  >  NEET Questions  >  If density of copper is 8.94 g/cm^3, the numb... Start Learning for Free
If density of copper is 8.94 g/cm^3, the number of Faradays required to plate an area (10cmx10cm) of thickness of 10^-2cm using CuSO4 solution as electrolyte is A) 0.1 F B) 0.28 F C) 0.4 F D) 0.5 F?
Most Upvoted Answer
If density of copper is 8.94 g/cm^3, the number of Faradays required t...
Community Answer
If density of copper is 8.94 g/cm^3, the number of Faradays required t...
Determining the number of Faradays required to plate an area of copper

Given:
Density of copper = 8.94 g/cm^3
Area to be plated = 10 cm x 10 cm
Thickness of plating = 10^-2 cm

To determine the number of Faradays required, we need to calculate the mass of copper required for plating and then convert it into moles.

Step 1: Calculating the mass of copper
The formula for calculating the mass of a substance is given by:

Mass = Density x Volume

Volume = Area x Thickness

In this case, the area is 10 cm x 10 cm and the thickness is 10^-2 cm.

Volume = 10 cm x 10 cm x 10^-2 cm = 10 cm^3

Now, substituting the values into the mass formula:

Mass = 8.94 g/cm^3 x 10 cm^3 = 89.4 g

Step 2: Converting mass to moles
To convert mass to moles, we need to use the molar mass of copper. The molar mass of copper is 63.55 g/mol.

Moles = Mass / Molar mass

Moles = 89.4 g / 63.55 g/mol = 1.406 mol

Step 3: Calculating the number of Faradays
1 Faraday is equal to 1 mole of electrons. The equation relating moles of substance and Faradays is given by:

Faradays = Moles / Avogadro's number

Where Avogadro's number is 6.022 x 10^23 mol^-1.

Faradays = 1.406 mol / (6.022 x 10^23 mol^-1) = 2.33 x 10^-24 F

Answer:
The number of Faradays required to plate an area of 10 cm x 10 cm with a thickness of 10^-2 cm using CuSO4 solution as an electrolyte is approximately 2.33 x 10^-24 F.

Note:
None of the given answer options matches the calculated value. It is possible that there is an error in the provided options or in the calculations.
Attention NEET Students!
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.
Explore Courses for NEET exam

Top Courses for NEET

If density of copper is 8.94 g/cm^3, the number of Faradays required to plate an area (10cmx10cm) of thickness of 10^-2cm using CuSO4 solution as electrolyte is A) 0.1 F B) 0.28 F C) 0.4 F D) 0.5 F?
Question Description
If density of copper is 8.94 g/cm^3, the number of Faradays required to plate an area (10cmx10cm) of thickness of 10^-2cm using CuSO4 solution as electrolyte is A) 0.1 F B) 0.28 F C) 0.4 F D) 0.5 F? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about If density of copper is 8.94 g/cm^3, the number of Faradays required to plate an area (10cmx10cm) of thickness of 10^-2cm using CuSO4 solution as electrolyte is A) 0.1 F B) 0.28 F C) 0.4 F D) 0.5 F? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If density of copper is 8.94 g/cm^3, the number of Faradays required to plate an area (10cmx10cm) of thickness of 10^-2cm using CuSO4 solution as electrolyte is A) 0.1 F B) 0.28 F C) 0.4 F D) 0.5 F?.
Solutions for If density of copper is 8.94 g/cm^3, the number of Faradays required to plate an area (10cmx10cm) of thickness of 10^-2cm using CuSO4 solution as electrolyte is A) 0.1 F B) 0.28 F C) 0.4 F D) 0.5 F? in English & in Hindi are available as part of our courses for NEET. Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of If density of copper is 8.94 g/cm^3, the number of Faradays required to plate an area (10cmx10cm) of thickness of 10^-2cm using CuSO4 solution as electrolyte is A) 0.1 F B) 0.28 F C) 0.4 F D) 0.5 F? defined & explained in the simplest way possible. Besides giving the explanation of If density of copper is 8.94 g/cm^3, the number of Faradays required to plate an area (10cmx10cm) of thickness of 10^-2cm using CuSO4 solution as electrolyte is A) 0.1 F B) 0.28 F C) 0.4 F D) 0.5 F?, a detailed solution for If density of copper is 8.94 g/cm^3, the number of Faradays required to plate an area (10cmx10cm) of thickness of 10^-2cm using CuSO4 solution as electrolyte is A) 0.1 F B) 0.28 F C) 0.4 F D) 0.5 F? has been provided alongside types of If density of copper is 8.94 g/cm^3, the number of Faradays required to plate an area (10cmx10cm) of thickness of 10^-2cm using CuSO4 solution as electrolyte is A) 0.1 F B) 0.28 F C) 0.4 F D) 0.5 F? theory, EduRev gives you an ample number of questions to practice If density of copper is 8.94 g/cm^3, the number of Faradays required to plate an area (10cmx10cm) of thickness of 10^-2cm using CuSO4 solution as electrolyte is A) 0.1 F B) 0.28 F C) 0.4 F D) 0.5 F? tests, examples and also practice NEET tests.
Explore Courses for NEET exam

Top Courses for NEET

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev