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2.5 Faraday of electricity is passed through a solution of CuSO4. The number of gram equivalents of copper deposited on the cathode will be A) 1 B) 2 C) 2.5 D) 1.25?
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2.5 Faraday of electricity is passed through a solution of CuSO4. The ...
Answer:
Introduction:
In this question, we are given that 2.5 Faraday of electricity is passed through a solution of CuSO4, and we have to find the number of gram equivalents of copper deposited on the cathode.
Solution:
The chemical formula of copper sulfate is CuSO4. When it is dissolved in water, it dissociates into Cu2+ and SO42- ions.
CuSO4 + H2O → Cu2+ + SO42-
During electrolysis, Cu2+ ions get reduced and deposited on the cathode.
Cu2+ + 2e- → Cu
Each copper ion requires two electrons to get reduced to copper. Therefore, the number of gram equivalents of copper deposited on the cathode can be calculated using the following formula:
Gram equivalents of copper = (Number of Faradays of electricity × Atomic weight of copper) ÷ Valency of copper
The atomic weight of copper is 63.5, and its valency is 2.
Substituting the given values in the formula, we get:
Gram equivalents of copper = (2.5 × 63.5) ÷ 2 = 79.375
Therefore, the number of gram equivalents of copper deposited on the cathode will be 79.375.
Conclusion:
In conclusion, when 2.5 Faraday of electricity is passed through a solution of CuSO4, the number of gram equivalents of copper deposited on the cathode will be 79.375.
Community Answer
2.5 Faraday of electricity is passed through a solution of CuSO4. The ...
Cu^2+ +2e -> Cu
for 1 mole of cu2+ -> 2 farad electricity
2 farad electricity -> 1 mole copper deposited
1 farad electricity -> 1/2 mole copper deposited
2.5 farad electricity -> 1.25 mole copper deposite
for 1 mole of cu2+ -> 2 farad electricity
2 farad electricity -> 1 mole copper deposited
1 farad electricity -> 1/2 mole copper deposited
2.5 farad electricity -> 1.25 mole copper deposite
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2.5 Faraday of electricity is passed through a solution of CuSO4. The number of gram equivalents of copper deposited on the cathode will be A) 1 B) 2 C) 2.5 D) 1.25?
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2.5 Faraday of electricity is passed through a solution of CuSO4. The number of gram equivalents of copper deposited on the cathode will be A) 1 B) 2 C) 2.5 D) 1.25? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 2.5 Faraday of electricity is passed through a solution of CuSO4. The number of gram equivalents of copper deposited on the cathode will be A) 1 B) 2 C) 2.5 D) 1.25? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 2.5 Faraday of electricity is passed through a solution of CuSO4. The number of gram equivalents of copper deposited on the cathode will be A) 1 B) 2 C) 2.5 D) 1.25?.
2.5 Faraday of electricity is passed through a solution of CuSO4. The number of gram equivalents of copper deposited on the cathode will be A) 1 B) 2 C) 2.5 D) 1.25? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 2.5 Faraday of electricity is passed through a solution of CuSO4. The number of gram equivalents of copper deposited on the cathode will be A) 1 B) 2 C) 2.5 D) 1.25? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 2.5 Faraday of electricity is passed through a solution of CuSO4. The number of gram equivalents of copper deposited on the cathode will be A) 1 B) 2 C) 2.5 D) 1.25?.
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