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2.5 Faraday of electricity is passed through a solution of CuSO4. The number of gram equivalents of copper deposited on the cathode will be A) 1 B) 2 C) 2.5 D) 1.25?
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2.5 Faraday of electricity is passed through a solution of CuSO4. The ...
Answer:


Introduction:


In this question, we are given that 2.5 Faraday of electricity is passed through a solution of CuSO4, and we have to find the number of gram equivalents of copper deposited on the cathode.

Solution:


The chemical formula of copper sulfate is CuSO4. When it is dissolved in water, it dissociates into Cu2+ and SO42- ions.

CuSO4 + H2O → Cu2+ + SO42-

During electrolysis, Cu2+ ions get reduced and deposited on the cathode.

Cu2+ + 2e- → Cu

Each copper ion requires two electrons to get reduced to copper. Therefore, the number of gram equivalents of copper deposited on the cathode can be calculated using the following formula:

Gram equivalents of copper = (Number of Faradays of electricity × Atomic weight of copper) ÷ Valency of copper

The atomic weight of copper is 63.5, and its valency is 2.

Substituting the given values in the formula, we get:

Gram equivalents of copper = (2.5 × 63.5) ÷ 2 = 79.375

Therefore, the number of gram equivalents of copper deposited on the cathode will be 79.375.

Conclusion:


In conclusion, when 2.5 Faraday of electricity is passed through a solution of CuSO4, the number of gram equivalents of copper deposited on the cathode will be 79.375.
Community Answer
2.5 Faraday of electricity is passed through a solution of CuSO4. The ...
Cu^2+ +2e -> Cu
for 1 mole of cu2+ -> 2 farad electricity
2 farad electricity -> 1 mole copper deposited
1 farad electricity -> 1/2 mole copper deposited
2.5 farad electricity -> 1.25 mole copper deposite
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2.5 Faraday of electricity is passed through a solution of CuSO4. The number of gram equivalents of copper deposited on the cathode will be A) 1 B) 2 C) 2.5 D) 1.25?
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