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20ml of NO combines with 10 ml of oxygen at STP to give NO2 .final vol is
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20ml of NO combines with 10 ml of oxygen at STP to give NO2 .final vol...
Solution:

Given:
Volume of NO = 20 ml
Volume of oxygen = 10 ml

To find:
Final volume of NO2

We can start by writing a balanced chemical equation for the reaction between NO and oxygen to form NO2:

2 NO + O2 β†’ 2 NO2

According to the balanced equation, it can be observed that 2 volumes of NO react with 1 volume of oxygen to produce 2 volumes of NO2.

Using the given volumes, we can determine the number of volumes involved in the reaction:

Volume of NO = 20 ml
Volume of oxygen = 10 ml

From the balanced equation, we can see that the ratio of volumes is 2:1. Therefore, we can say that for every 2 volumes of NO, 1 volume of oxygen will be consumed.

Since we have 20 ml of NO, we can calculate the amount of oxygen required using the ratio:

20 ml NO Γ— (1 volume O2 / 2 volumes NO) = 10 ml O2

So, the given volume of oxygen (10 ml) is exactly the amount required for the reaction.

Now, let's determine the final volume of NO2 produced. According to the balanced equation, the ratio of volumes is 2:2. Therefore, for every 2 volumes of NO2 produced, 2 volumes of NO and 1 volume of oxygen are consumed.

Since we have consumed 20 ml of NO, the final volume of NO2 produced will be:

20 ml NO Γ— (2 volumes NO2 / 2 volumes NO) = 20 ml NO2

Thus, the final volume of NO2 produced is 20 ml.

In summary:

- 20 ml of NO reacts with 10 ml of oxygen.
- The given volume of oxygen is exactly the amount required for the reaction.
- The final volume of NO2 produced is 20 ml.
Community Answer
20ml of NO combines with 10 ml of oxygen at STP to give NO2 .final vol...
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