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Standard free energies of formation (in kJ/mol) at 298K are -237.2, -394.4 and -8.2 for H2O(l), CO2(g) and pentane(g) respectively. The value of E(not)cell for the pentane -oxygen fuel cell is A) 0.0968V B) 1.968V C) 2.0968V D) 1.0968V? plz explain?
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Standard free energies of formation (in kJ/mol) at 298K are -237.2, -3...
Calculation of E(not)cell for the Pentane-Oxygen Fuel Cell
Given standard free energies of formation of H2O(l), CO2(g) and pentane(g) at 298K are -237.2, -394.4 and -8.2 kJ/mol, respectively.
The equation for the reaction taking place in the pentane-oxygen fuel cell is as follows:
C5H12 + 8O2 → 5CO2 + 6H2O
Step 1: Calculate the standard free energy change (ΔG˚) for the reaction.
ΔG˚ = ΣnΔG˚f(products) - ΣnΔG˚f(reactants)
ΔG˚ = [5(-394.4 kJ/mol) + 6(-237.2 kJ/mol)] - [(-8.2 kJ/mol)]
ΔG˚ = -2863.2 kJ/mol
Step 2: Calculate the number of moles of electrons transferred (n).
In the above reaction, 10 moles of electrons are transferred, as 5 moles of CO2 and 6 moles of H2O are formed from the oxidation of 1 mole of pentane.
n = 10
Step 3: Calculate the Faraday constant (F).
F = 96485 C/mol
Step 4: Calculate E(not)cell using the equation:
E(not)cell = - ΔG˚ / (nF)
E(not)cell = - (-2863.2 kJ/mol) / (10 x 96485 C/mol)
E(not)cell = 0.2968 V
Therefore, the value of E(not)cell for the pentane-oxygen fuel cell is 0.2968 V, which is option A.
Given standard free energies of formation of H2O(l), CO2(g) and pentane(g) at 298K are -237.2, -394.4 and -8.2 kJ/mol, respectively.
The equation for the reaction taking place in the pentane-oxygen fuel cell is as follows:
C5H12 + 8O2 → 5CO2 + 6H2O
Step 1: Calculate the standard free energy change (ΔG˚) for the reaction.
ΔG˚ = ΣnΔG˚f(products) - ΣnΔG˚f(reactants)
ΔG˚ = [5(-394.4 kJ/mol) + 6(-237.2 kJ/mol)] - [(-8.2 kJ/mol)]
ΔG˚ = -2863.2 kJ/mol
Step 2: Calculate the number of moles of electrons transferred (n).
In the above reaction, 10 moles of electrons are transferred, as 5 moles of CO2 and 6 moles of H2O are formed from the oxidation of 1 mole of pentane.
n = 10
Step 3: Calculate the Faraday constant (F).
F = 96485 C/mol
Step 4: Calculate E(not)cell using the equation:
E(not)cell = - ΔG˚ / (nF)
E(not)cell = - (-2863.2 kJ/mol) / (10 x 96485 C/mol)
E(not)cell = 0.2968 V
Therefore, the value of E(not)cell for the pentane-oxygen fuel cell is 0.2968 V, which is option A.
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Standard free energies of formation (in kJ/mol) at 298K are -237.2, -3...
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Standard free energies of formation (in kJ/mol) at 298K are -237.2, -394.4 and -8.2 for H2O(l), CO2(g) and pentane(g) respectively. The value of E(not)cell for the pentane -oxygen fuel cell is A) 0.0968V B) 1.968V C) 2.0968V D) 1.0968V? plz explain?
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Standard free energies of formation (in kJ/mol) at 298K are -237.2, -394.4 and -8.2 for H2O(l), CO2(g) and pentane(g) respectively. The value of E(not)cell for the pentane -oxygen fuel cell is A) 0.0968V B) 1.968V C) 2.0968V D) 1.0968V? plz explain? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Standard free energies of formation (in kJ/mol) at 298K are -237.2, -394.4 and -8.2 for H2O(l), CO2(g) and pentane(g) respectively. The value of E(not)cell for the pentane -oxygen fuel cell is A) 0.0968V B) 1.968V C) 2.0968V D) 1.0968V? plz explain? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Standard free energies of formation (in kJ/mol) at 298K are -237.2, -394.4 and -8.2 for H2O(l), CO2(g) and pentane(g) respectively. The value of E(not)cell for the pentane -oxygen fuel cell is A) 0.0968V B) 1.968V C) 2.0968V D) 1.0968V? plz explain?.
Standard free energies of formation (in kJ/mol) at 298K are -237.2, -394.4 and -8.2 for H2O(l), CO2(g) and pentane(g) respectively. The value of E(not)cell for the pentane -oxygen fuel cell is A) 0.0968V B) 1.968V C) 2.0968V D) 1.0968V? plz explain? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Standard free energies of formation (in kJ/mol) at 298K are -237.2, -394.4 and -8.2 for H2O(l), CO2(g) and pentane(g) respectively. The value of E(not)cell for the pentane -oxygen fuel cell is A) 0.0968V B) 1.968V C) 2.0968V D) 1.0968V? plz explain? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Standard free energies of formation (in kJ/mol) at 298K are -237.2, -394.4 and -8.2 for H2O(l), CO2(g) and pentane(g) respectively. The value of E(not)cell for the pentane -oxygen fuel cell is A) 0.0968V B) 1.968V C) 2.0968V D) 1.0968V? plz explain?.
Solutions for Standard free energies of formation (in kJ/mol) at 298K are -237.2, -394.4 and -8.2 for H2O(l), CO2(g) and pentane(g) respectively. The value of E(not)cell for the pentane -oxygen fuel cell is A) 0.0968V B) 1.968V C) 2.0968V D) 1.0968V? plz explain? in English & in Hindi are available as part of our courses for NEET.
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Standard free energies of formation (in kJ/mol) at 298K are -237.2, -394.4 and -8.2 for H2O(l), CO2(g) and pentane(g) respectively. The value of E(not)cell for the pentane -oxygen fuel cell is A) 0.0968V B) 1.968V C) 2.0968V D) 1.0968V? plz explain?, a detailed solution for Standard free energies of formation (in kJ/mol) at 298K are -237.2, -394.4 and -8.2 for H2O(l), CO2(g) and pentane(g) respectively. The value of E(not)cell for the pentane -oxygen fuel cell is A) 0.0968V B) 1.968V C) 2.0968V D) 1.0968V? plz explain? has been provided alongside types of Standard free energies of formation (in kJ/mol) at 298K are -237.2, -394.4 and -8.2 for H2O(l), CO2(g) and pentane(g) respectively. The value of E(not)cell for the pentane -oxygen fuel cell is A) 0.0968V B) 1.968V C) 2.0968V D) 1.0968V? plz explain? theory, EduRev gives you an
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