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An organic compound X on treatment with acidified k2Cr2O7 gives compound Y which reacts with I2 and sodium carbonate to form triiodomethane. The compound X can be
- a)CH3OH
- b)CH3COCH3
- c)CH3CHO
- d)CH3CHOHCH3
Correct answer is option 'D'. Can you explain this answer?
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An organic compound X on treatment with acidified k2Cr2O7 gives compou...
Identification of Organic Compound X
To identify the organic compound X, we need to analyze the given information:
- On treatment with acidified K2Cr2O7, X forms Y.
- Y reacts with I2 and sodium carbonate to form triiodomethane.
This information suggests that X contains a functional group that can be oxidized by acidified K2Cr2O7 to form a compound that can react with I2 and sodium carbonate to form triiodomethane. The functional group that fits this description is an alcohol (-OH) group.
Reasoning
- Acidified K2Cr2O7 is a strong oxidizing agent that can oxidize primary and secondary alcohols to form carboxylic acids and ketones, respectively.
- On oxidation of a primary alcohol, two hydrogen atoms are lost, whereas on oxidation of a secondary alcohol, one hydrogen atom is lost.
- Triiodomethane (CHI3) is commonly known as iodoform and is formed by the reaction of a methyl ketone or a primary alcohol with iodine and a base (such as sodium carbonate).
Therefore, the organic compound X that can form Y on treatment with acidified K2Cr2O7 and can react with I2 and sodium carbonate to form triiodomethane is a primary alcohol with a methyl group attached to the alcohol carbon.
Answer
Hence, the correct option is D, which represents the primary alcohol CH3CH(OH)CH3, also known as 2-propanol or isopropyl alcohol.
To identify the organic compound X, we need to analyze the given information:
- On treatment with acidified K2Cr2O7, X forms Y.
- Y reacts with I2 and sodium carbonate to form triiodomethane.
This information suggests that X contains a functional group that can be oxidized by acidified K2Cr2O7 to form a compound that can react with I2 and sodium carbonate to form triiodomethane. The functional group that fits this description is an alcohol (-OH) group.
Reasoning
- Acidified K2Cr2O7 is a strong oxidizing agent that can oxidize primary and secondary alcohols to form carboxylic acids and ketones, respectively.
- On oxidation of a primary alcohol, two hydrogen atoms are lost, whereas on oxidation of a secondary alcohol, one hydrogen atom is lost.
- Triiodomethane (CHI3) is commonly known as iodoform and is formed by the reaction of a methyl ketone or a primary alcohol with iodine and a base (such as sodium carbonate).
Therefore, the organic compound X that can form Y on treatment with acidified K2Cr2O7 and can react with I2 and sodium carbonate to form triiodomethane is a primary alcohol with a methyl group attached to the alcohol carbon.
Answer
Hence, the correct option is D, which represents the primary alcohol CH3CH(OH)CH3, also known as 2-propanol or isopropyl alcohol.
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An organic compound X on treatment with acidified k2Cr2O7 gives compound Y which reacts with I2 and sodium carbonate to form triiodomethane. The compound X can bea)CH3OHb)CH3COCH3c)CH3CHOd)CH3CHOHCH3Correct answer is option 'D'. Can you explain this answer?
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An organic compound X on treatment with acidified k2Cr2O7 gives compound Y which reacts with I2 and sodium carbonate to form triiodomethane. The compound X can bea)CH3OHb)CH3COCH3c)CH3CHOd)CH3CHOHCH3Correct answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about An organic compound X on treatment with acidified k2Cr2O7 gives compound Y which reacts with I2 and sodium carbonate to form triiodomethane. The compound X can bea)CH3OHb)CH3COCH3c)CH3CHOd)CH3CHOHCH3Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An organic compound X on treatment with acidified k2Cr2O7 gives compound Y which reacts with I2 and sodium carbonate to form triiodomethane. The compound X can bea)CH3OHb)CH3COCH3c)CH3CHOd)CH3CHOHCH3Correct answer is option 'D'. Can you explain this answer?.
An organic compound X on treatment with acidified k2Cr2O7 gives compound Y which reacts with I2 and sodium carbonate to form triiodomethane. The compound X can bea)CH3OHb)CH3COCH3c)CH3CHOd)CH3CHOHCH3Correct answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about An organic compound X on treatment with acidified k2Cr2O7 gives compound Y which reacts with I2 and sodium carbonate to form triiodomethane. The compound X can bea)CH3OHb)CH3COCH3c)CH3CHOd)CH3CHOHCH3Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An organic compound X on treatment with acidified k2Cr2O7 gives compound Y which reacts with I2 and sodium carbonate to form triiodomethane. The compound X can bea)CH3OHb)CH3COCH3c)CH3CHOd)CH3CHOHCH3Correct answer is option 'D'. Can you explain this answer?.
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An organic compound X on treatment with acidified k2Cr2O7 gives compound Y which reacts with I2 and sodium carbonate to form triiodomethane. The compound X can bea)CH3OHb)CH3COCH3c)CH3CHOd)CH3CHOHCH3Correct answer is option 'D'. Can you explain this answer?, a detailed solution for An organic compound X on treatment with acidified k2Cr2O7 gives compound Y which reacts with I2 and sodium carbonate to form triiodomethane. The compound X can bea)CH3OHb)CH3COCH3c)CH3CHOd)CH3CHOHCH3Correct answer is option 'D'. Can you explain this answer? has been provided alongside types of An organic compound X on treatment with acidified k2Cr2O7 gives compound Y which reacts with I2 and sodium carbonate to form triiodomethane. The compound X can bea)CH3OHb)CH3COCH3c)CH3CHOd)CH3CHOHCH3Correct answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
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