A cyclotron is operated at an oscillator frequency of 24MHz and has a dees radius of 60cm Ti accelerate the deuterons the mangnitude of magnetic field needed is?

Question

Answer

Apply the formula

B=2πmv/q

& get your answer dear..

Answer

Calculating Magnetic Field for Cyclotron

Given

Oscillator frequency = 24 MHz

Dees radius = 60 cm

Formula

The formula for calculating the required magnetic field for a cyclotron is:

B = (m*q)/(r*f)

B = magnetic field

m = mass of the particle

q = charge of the particle

r = radius of the dees

f = oscillator frequency

Solution

For deuterons:

m = 3.344 x 10^-27 kg

q = 1.602 x 10^-19 C

Substituting these values in the formula:

B = (3.344 x 10^-27 kg x 1.602 x 10^-19 C)/(0.6 m x 24 x 10^6 Hz)

B = 1.79 T

Explanation

A cyclotron is a type of particle accelerator that uses a magnetic field to accelerate charged particles. The particles are injected into the center of the cyclotron, where they are accelerated by an oscillating electric field. The magnetic field causes the particles to move in a circular path, with a radius determined by the strength of the field.

The formula for calculating the required magnetic field takes into account the mass and charge of the particle, as well as the radius of the dees and the frequency of the oscillator. By plugging in the given values for the deuterons and solving for B, we can determine the magnetic field needed to accelerate the particles in this cyclotron.

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