When an inert gas is filled in the place vacuum in a photo cell, thena)Photo-electric current is decreasedb)Photo-electric current is increasedc)Photo-electric current is remains the samed)Decrease or increase in photo-electric current does not depend upon the gas filledCorrect answer is option 'B'. Can you explain this answer?

Question

Answer

Explanation:

The photoelectric effect is a phenomenon where electrons are emitted from a metal surface when it is exposed to electromagnetic radiation, such as light. This effect is widely used in photoelectric cells which are used to convert light energy into electrical energy.

When an inert gas is filled in the place vacuum in a photo cell, the following changes occur:

1. Collision of electrons with gas atoms

The inert gas atoms present in the photo cell collide with the electrons that are emitted due to the photoelectric effect. This collision can cause the electrons to lose energy, reducing their kinetic energy.

2. Reduction in energy of emitted electrons

Due to the collision with gas atoms, the emitted electrons will have less energy than they would have had in a vacuum. This reduction in energy of the emitted electrons will cause a decrease in the photo-electric current.

3. Increased number of collisions

When an inert gas is filled in the place of vacuum, the number of gas atoms in the photo cell increases. This increases the chances of collisions between the emitted electrons and gas atoms leading to a further decrease in the photo-electric current.

Thus, the correct option is B) Photo-electric current is increased.

Answer

In the presence of inert gas photoelectrons emitted by cathode ionise the gas by collision and hence the current increases.

Answer

Solution : In the pressure of inert gas photoelectrons emitted by cathode ionize the gas by collision and hence the current increases.

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