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The frequency of a light wave in a material is 2× 10^14 Hz and wave length is 5000Angstrongs . The refractive index of material will be 1) 1.50 2)3 3)1.33 4)1.40?
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The refractive index of a material can be found using the formula:

n = c/v

Where:
n = refractive index
c = speed of light in vacuum
v = speed of light in the material

The speed of light in vacuum is a constant:

c = 3 x 10^8 m/s

To find the speed of light in the material, we can use the formula:

v = λf

Where:
v = speed of light in the material
λ = wavelength of the light wave
f = frequency of the light wave

Given values:
Frequency (f) = 2 x 10^14 Hz
Wavelength (λ) = 5000 Angstroms = 5000 x 10^-10 m

Calculating the speed of light in the material:
v = λf
= (5000 x 10^-10 m)(2 x 10^14 Hz)
= 1 x 10^10 m/s

Calculating the refractive index:
n = c/v
= (3 x 10^8 m/s)/(1 x 10^10 m/s)
= 0.03

The refractive index of the material is approximately 0.03.

None of the given options (1.50, 3, 1.33, 1.40) match the calculated value of 0.03.
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The frequency of a light wave in a material is 2× 10^14 Hz and wave length is 5000Angstrongs . The refractive index of material will be 1) 1.50 2)3 3)1.33 4)1.40?
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