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A 5 Kg body moving at 10 ms-1 strikes a 20Kg body at rest. The collision is inelastic and the 5Kg body comes to rest and the 20Kg body is set into motion. The velocity of the second body is
- a)2.5 ms-1 in the same direction of motion
- b)10 ms-1 in the original direction of motion
- c)5 ms-1 in the direction of motion
- d)5 ms-1 in the opposite direction of motion
Correct answer is option 'A'. Can you explain this answer?
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A 5 Kg body moving at 10 ms-1 strikes a 20Kg body at rest. The collisi...
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A 5 Kg body moving at 10 ms-1 strikes a 20Kg body at rest. The collisi...
Given information:
- Mass of the first body (5 kg) and its initial velocity (10 m/s).
- Mass of the second body (20 kg) is at rest initially.
Approach:
To solve this problem, we can use the principle of conservation of momentum. According to this principle, the total momentum before the collision is equal to the total momentum after the collision.
Solution:
Step 1: Calculate the initial momentum (p1) of the system before the collision.
The momentum (p) of an object is given by the product of its mass (m) and velocity (v).
So, the initial momentum of the first body is:
p1 = m1 * v1 = 5 kg * 10 m/s = 50 kgm/s.
Step 2: Calculate the final momentum (p2) of the system after the collision.
Since the first body comes to rest after the collision, its final velocity (v1f) is 0 m/s.
The final momentum of the first body is:
p1f = m1 * v1f = 5 kg * 0 m/s = 0 kgm/s.
The second body is set into motion after the collision, so its final velocity (v2f) is what we need to find.
Step 3: Apply the principle of conservation of momentum.
According to the principle of conservation of momentum, the total momentum before the collision (p1) is equal to the total momentum after the collision (p2).
So, we have:
p1 = p2
50 kgm/s = 0 kgm/s + m2 * v2f
50 kgm/s = 20 kg * v2f
Step 4: Solve for the final velocity (v2f) of the second body.
Divide both sides of the equation by the mass (m2) of the second body to solve for v2f:
v2f = 50 kgm/s / 20 kg
v2f = 2.5 m/s
Conclusion:
Therefore, the velocity of the second body after the collision is 2.5 m/s in the same direction as the initial motion of the first body. Hence, the correct answer is option 'A'.
- Mass of the first body (5 kg) and its initial velocity (10 m/s).
- Mass of the second body (20 kg) is at rest initially.
Approach:
To solve this problem, we can use the principle of conservation of momentum. According to this principle, the total momentum before the collision is equal to the total momentum after the collision.
Solution:
Step 1: Calculate the initial momentum (p1) of the system before the collision.
The momentum (p) of an object is given by the product of its mass (m) and velocity (v).
So, the initial momentum of the first body is:
p1 = m1 * v1 = 5 kg * 10 m/s = 50 kgm/s.
Step 2: Calculate the final momentum (p2) of the system after the collision.
Since the first body comes to rest after the collision, its final velocity (v1f) is 0 m/s.
The final momentum of the first body is:
p1f = m1 * v1f = 5 kg * 0 m/s = 0 kgm/s.
The second body is set into motion after the collision, so its final velocity (v2f) is what we need to find.
Step 3: Apply the principle of conservation of momentum.
According to the principle of conservation of momentum, the total momentum before the collision (p1) is equal to the total momentum after the collision (p2).
So, we have:
p1 = p2
50 kgm/s = 0 kgm/s + m2 * v2f
50 kgm/s = 20 kg * v2f
Step 4: Solve for the final velocity (v2f) of the second body.
Divide both sides of the equation by the mass (m2) of the second body to solve for v2f:
v2f = 50 kgm/s / 20 kg
v2f = 2.5 m/s
Conclusion:
Therefore, the velocity of the second body after the collision is 2.5 m/s in the same direction as the initial motion of the first body. Hence, the correct answer is option 'A'.
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A 5 Kg body moving at 10 ms-1 strikes a 20Kg body at rest. The collision is inelastic and the 5Kg body comes to rest and the 20Kg body is set into motion. The velocity of the second body isa)2.5 ms-1 in the same direction of motionb)10 ms-1 in the original direction of motionc)5 ms-1 in the direction of motiond)5 ms-1 in the opposite direction of motionCorrect answer is option 'A'. Can you explain this answer?
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A 5 Kg body moving at 10 ms-1 strikes a 20Kg body at rest. The collision is inelastic and the 5Kg body comes to rest and the 20Kg body is set into motion. The velocity of the second body isa)2.5 ms-1 in the same direction of motionb)10 ms-1 in the original direction of motionc)5 ms-1 in the direction of motiond)5 ms-1 in the opposite direction of motionCorrect answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A 5 Kg body moving at 10 ms-1 strikes a 20Kg body at rest. The collision is inelastic and the 5Kg body comes to rest and the 20Kg body is set into motion. The velocity of the second body isa)2.5 ms-1 in the same direction of motionb)10 ms-1 in the original direction of motionc)5 ms-1 in the direction of motiond)5 ms-1 in the opposite direction of motionCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 5 Kg body moving at 10 ms-1 strikes a 20Kg body at rest. The collision is inelastic and the 5Kg body comes to rest and the 20Kg body is set into motion. The velocity of the second body isa)2.5 ms-1 in the same direction of motionb)10 ms-1 in the original direction of motionc)5 ms-1 in the direction of motiond)5 ms-1 in the opposite direction of motionCorrect answer is option 'A'. Can you explain this answer?.
A 5 Kg body moving at 10 ms-1 strikes a 20Kg body at rest. The collision is inelastic and the 5Kg body comes to rest and the 20Kg body is set into motion. The velocity of the second body isa)2.5 ms-1 in the same direction of motionb)10 ms-1 in the original direction of motionc)5 ms-1 in the direction of motiond)5 ms-1 in the opposite direction of motionCorrect answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A 5 Kg body moving at 10 ms-1 strikes a 20Kg body at rest. The collision is inelastic and the 5Kg body comes to rest and the 20Kg body is set into motion. The velocity of the second body isa)2.5 ms-1 in the same direction of motionb)10 ms-1 in the original direction of motionc)5 ms-1 in the direction of motiond)5 ms-1 in the opposite direction of motionCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 5 Kg body moving at 10 ms-1 strikes a 20Kg body at rest. The collision is inelastic and the 5Kg body comes to rest and the 20Kg body is set into motion. The velocity of the second body isa)2.5 ms-1 in the same direction of motionb)10 ms-1 in the original direction of motionc)5 ms-1 in the direction of motiond)5 ms-1 in the opposite direction of motionCorrect answer is option 'A'. Can you explain this answer?.
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