NEET Exam > NEET Questions > A mixture of 2.3 g formic acid and 4.5 g oxal...
Start Learning for Free
A mixture of 2.3 g formic acid and 4.5 g oxalic acidis treated with conc. H2SO4. The evolved gaseousmixture is passed through KOH pellets. Weight (ing) of the remaining product at STP will be
- a)1.4
- b)3.0
- c)2.8
- d)4.4
Correct answer is option 'C'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
A mixture of 2.3 g formic acid and 4.5 g oxalic acidis treated with co...
Most Upvoted Answer
A mixture of 2.3 g formic acid and 4.5 g oxalic acidis treated with co...
Given:
Mass of formic acid = 2.3 g
Mass of oxalic acid = 4.5 g
When formic acid and oxalic acid are treated with conc. H2SO4, they undergo dehydration to form CO and CO2 gases.
HCOOH → CO + H2O
H2C2O4 → CO + CO2 + H2O
The evolved gas mixture is then passed through KOH pellets. KOH is a strong base and reacts with CO2 to form potassium carbonate (K2CO3), which is a solid.
CO2 + 2KOH → K2CO3 + H2O
CO is not absorbed by KOH pellets and remains in the gaseous state.
Now, we need to find the weight of the remaining product at STP. STP stands for standard temperature and pressure, which is 0°C and 1 atm pressure.
At STP, 1 mole of any gas occupies 22.4 L volume.
Let's calculate the moles of CO2 and CO gases evolved from the given mixture.
Molar mass of formic acid (HCOOH) = 46.03 g/mol
Molar mass of oxalic acid (H2C2O4) = 90.04 g/mol
Moles of formic acid = 2.3 g / 46.03 g/mol = 0.05 mol
Moles of oxalic acid = 4.5 g / 90.04 g/mol = 0.05 mol
From the balanced equations, we can see that one mole of formic acid produces one mole of CO2 gas and one mole of oxalic acid produces one mole of CO gas.
Moles of CO2 gas evolved = 0.05 mol
Moles of CO gas evolved = 0.05 mol
Volume of CO2 gas at STP = 0.05 mol × 22.4 L/mol = 1.12 L
Volume of CO gas at STP = 0.05 mol × 22.4 L/mol = 1.12 L
Now, the evolved gas mixture is passed through KOH pellets, which absorb CO2 gas and form K2CO3 solid. Therefore, the volume of gas remaining after passing through KOH pellets is the volume of CO gas, which is 1.12 L.
Finally, we need to calculate the weight of this remaining gas at STP. The molar mass of CO gas is 28.01 g/mol.
Mass of CO gas at STP = 0.05 mol × 28.01 g/mol = 1.4 g
Therefore, the weight of the remaining product at STP is 1.4 g.
Hence, the correct option is (c) 2.8.
Mass of formic acid = 2.3 g
Mass of oxalic acid = 4.5 g
When formic acid and oxalic acid are treated with conc. H2SO4, they undergo dehydration to form CO and CO2 gases.
HCOOH → CO + H2O
H2C2O4 → CO + CO2 + H2O
The evolved gas mixture is then passed through KOH pellets. KOH is a strong base and reacts with CO2 to form potassium carbonate (K2CO3), which is a solid.
CO2 + 2KOH → K2CO3 + H2O
CO is not absorbed by KOH pellets and remains in the gaseous state.
Now, we need to find the weight of the remaining product at STP. STP stands for standard temperature and pressure, which is 0°C and 1 atm pressure.
At STP, 1 mole of any gas occupies 22.4 L volume.
Let's calculate the moles of CO2 and CO gases evolved from the given mixture.
Molar mass of formic acid (HCOOH) = 46.03 g/mol
Molar mass of oxalic acid (H2C2O4) = 90.04 g/mol
Moles of formic acid = 2.3 g / 46.03 g/mol = 0.05 mol
Moles of oxalic acid = 4.5 g / 90.04 g/mol = 0.05 mol
From the balanced equations, we can see that one mole of formic acid produces one mole of CO2 gas and one mole of oxalic acid produces one mole of CO gas.
Moles of CO2 gas evolved = 0.05 mol
Moles of CO gas evolved = 0.05 mol
Volume of CO2 gas at STP = 0.05 mol × 22.4 L/mol = 1.12 L
Volume of CO gas at STP = 0.05 mol × 22.4 L/mol = 1.12 L
Now, the evolved gas mixture is passed through KOH pellets, which absorb CO2 gas and form K2CO3 solid. Therefore, the volume of gas remaining after passing through KOH pellets is the volume of CO gas, which is 1.12 L.
Finally, we need to calculate the weight of this remaining gas at STP. The molar mass of CO gas is 28.01 g/mol.
Mass of CO gas at STP = 0.05 mol × 28.01 g/mol = 1.4 g
Therefore, the weight of the remaining product at STP is 1.4 g.
Hence, the correct option is (c) 2.8.
Attention NEET Students!
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.
|
Explore Courses for NEET exam
|
|
Similar NEET Doubts
Top Courses for NEETView all
A mixture of 2.3 g formic acid and 4.5 g oxalic acidis treated with conc. H2SO4. The evolved gaseousmixture is passed through KOH pellets. Weight (ing) of the remaining product at STP will bea)1.4b)3.0c)2.8d)4.4Correct answer is option 'C'. Can you explain this answer?
Question Description
A mixture of 2.3 g formic acid and 4.5 g oxalic acidis treated with conc. H2SO4. The evolved gaseousmixture is passed through KOH pellets. Weight (ing) of the remaining product at STP will bea)1.4b)3.0c)2.8d)4.4Correct answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A mixture of 2.3 g formic acid and 4.5 g oxalic acidis treated with conc. H2SO4. The evolved gaseousmixture is passed through KOH pellets. Weight (ing) of the remaining product at STP will bea)1.4b)3.0c)2.8d)4.4Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A mixture of 2.3 g formic acid and 4.5 g oxalic acidis treated with conc. H2SO4. The evolved gaseousmixture is passed through KOH pellets. Weight (ing) of the remaining product at STP will bea)1.4b)3.0c)2.8d)4.4Correct answer is option 'C'. Can you explain this answer?.
A mixture of 2.3 g formic acid and 4.5 g oxalic acidis treated with conc. H2SO4. The evolved gaseousmixture is passed through KOH pellets. Weight (ing) of the remaining product at STP will bea)1.4b)3.0c)2.8d)4.4Correct answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A mixture of 2.3 g formic acid and 4.5 g oxalic acidis treated with conc. H2SO4. The evolved gaseousmixture is passed through KOH pellets. Weight (ing) of the remaining product at STP will bea)1.4b)3.0c)2.8d)4.4Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A mixture of 2.3 g formic acid and 4.5 g oxalic acidis treated with conc. H2SO4. The evolved gaseousmixture is passed through KOH pellets. Weight (ing) of the remaining product at STP will bea)1.4b)3.0c)2.8d)4.4Correct answer is option 'C'. Can you explain this answer?.
Solutions for A mixture of 2.3 g formic acid and 4.5 g oxalic acidis treated with conc. H2SO4. The evolved gaseousmixture is passed through KOH pellets. Weight (ing) of the remaining product at STP will bea)1.4b)3.0c)2.8d)4.4Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET.
Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of A mixture of 2.3 g formic acid and 4.5 g oxalic acidis treated with conc. H2SO4. The evolved gaseousmixture is passed through KOH pellets. Weight (ing) of the remaining product at STP will bea)1.4b)3.0c)2.8d)4.4Correct answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A mixture of 2.3 g formic acid and 4.5 g oxalic acidis treated with conc. H2SO4. The evolved gaseousmixture is passed through KOH pellets. Weight (ing) of the remaining product at STP will bea)1.4b)3.0c)2.8d)4.4Correct answer is option 'C'. Can you explain this answer?, a detailed solution for A mixture of 2.3 g formic acid and 4.5 g oxalic acidis treated with conc. H2SO4. The evolved gaseousmixture is passed through KOH pellets. Weight (ing) of the remaining product at STP will bea)1.4b)3.0c)2.8d)4.4Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of A mixture of 2.3 g formic acid and 4.5 g oxalic acidis treated with conc. H2SO4. The evolved gaseousmixture is passed through KOH pellets. Weight (ing) of the remaining product at STP will bea)1.4b)3.0c)2.8d)4.4Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A mixture of 2.3 g formic acid and 4.5 g oxalic acidis treated with conc. H2SO4. The evolved gaseousmixture is passed through KOH pellets. Weight (ing) of the remaining product at STP will bea)1.4b)3.0c)2.8d)4.4Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice NEET tests.
|
|
Explore Courses for NEET exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup