A trader mixes 6ltr of milk costing 5000 rupees with 7ltr of milk costing 6000 rupees per litre. The trader also mixes some quantity of water to the mixture so as to bring the price to 4800 per litre. How many litres of water is addeda)1ltrb)2ltrc)3ltrd)4ltre)None of theseCorrect answer is option 'B'. Can you explain this answer?

Question

Answer

Given:
- 6 litres of milk costing 5000 rupees
- 7 litres of milk costing 6000 rupees per litre
- Quantity of water to be added to bring the price to 4800 per litre

To find:
- How many litres of water is added

Solution:

Step 1:
Let’s assume that x litres of water is added to the mixture.
After adding x litres of water, the total volume of the mixture will be:

6 + 7 + x = 13 + x litres

Step 2:
Now, let’s calculate the total cost of the mixture:

Cost of 6 litres of milk = 5000 rupees
Cost of 7 litres of milk = 7 × 6000 = 42000 rupees

Total cost of milk = 5000 + 42000 = 47000 rupees

Since the cost of the mixture should be 4800 per litre, the total cost of the mixture should be:

(13 + x) × 4800

Step 3:
Now, we can equate the two costs to get an equation in terms of x:

(13 + x) × 4800 = 47000

Simplifying the equation, we get:

62400 + 4800x = 47000

4800x = 47000 - 62400

4800x = -15400

x = -15400/4800

x = -3.208

Step 4:
Since we cannot add negative quantity of water, we can conclude that it is not possible to bring down the cost to 4800 rupees per litre.

Therefore, the correct answer is option (B) None of these.

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