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The above is a plot of binding energy per nucleon Eb, against the nuclear mass M;, A, B, C, D, E, F correspond to different nuclei. Consider four reactions:
(i) A + B → C + ε
(ii) C → A + B + ε
(iii) D + E → F + ε and
(iv) F → D + E + ε
Where ε is the energy released ? In which reactions is ε positive?
  • a)
    (i) and (iv)
  • b)
    (i) and (iii)
  • c)
    (ii) and (iv)
  • d)
    (ii) and (iii)
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
The above is a plot of binding energy per nucleon Eb, against the nucl...
Answer is (a) because the nuclei whose binding per nucleon is more with less atomic mass are very much stable and the nuclei with much larger atomic mass are very unstable. Like most stable nuclei is of Fe whose atomic no. is 26 and mass no. 56.
so from the graph we can see that A & B are less stable than C because of less Eb so it will release +ve energy € to give more stable C. so reaction 1 is right and in reaction 4 also larger nuclei F which is very unstable with least Eb will release +ve energy € to form stable D&E.
I hope it helps!
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The above is a plot of binding energy per nucleon Eb, against the nuclear mass M;, A, B, C, D, E, F correspond to different nuclei. Consider four reactions:(i) A + B → C + ε(ii) C → A + B + ε(iii) D + E → F + ε and(iv) F → D + E + εWhere ε is the energy released ? In which reactions is ε positive?a)(i) and (iv)b)(i) and (iii)c)(ii) and (iv)d)(ii) and (iii)Correct answer is option 'A'. Can you explain this answer?
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