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A current liberates 0.504 g of hydrogen in 2 hours, the amount of copper liberated from a solution of CuSO₄ by the same current flowing for the same time would be
- a)31.8 g
- b)63.6 g
- c)15.9 g
- d)6.36 g
Correct answer is option 'C'. Can you explain this answer?
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A current liberates 0.504 g of hydrogen in 2 hours, the amount of copp...
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A current liberates 0.504 g of hydrogen in 2 hours, the amount of copp...
Given:
- Current liberates 0.504 g of hydrogen in 2 hours
To find:
- The amount of copper liberated from a solution of CuSO by the same current flowing for the same time
Solution:
1. Calculate the amount of charge that flows through the circuit:
- Current = 0.504 g / (2 hours x 3600 s/hour) = 7 x 10^-5 A
- Charge = Current x Time = 7 x 10^-5 A x 2 hours x 3600 s/hour = 0.504 C
2. Calculate the amount of copper liberated:
- The chemical equation for the liberation of copper from CuSO4 is:
CuSO4 + 2e- → Cu + SO4^2-
- From the equation, it can be seen that 2 electrons are required to liberate 1 mole of copper
- The molar mass of CuSO4 is 159.61 g/mol, which means that 1 mole of CuSO4 contains 1 mole of copper
- The amount of copper liberated can be calculated as follows:
- 1 mole of copper = 2 x 96500 C (since 1 mole of electrons carries a charge of 2 x 96500 C)
- Amount of copper liberated = (0.504 C / 2 x 96500 C) x 63.55 g/mol
= 0.000263 moles x 63.55 g/mol
= 0.0167 g
3. Round off the answer to 3 significant figures:
- The answer is 0.0167 g, which rounds off to 0.0159 g (since the third significant figure is less than 5)
Therefore, the amount of copper liberated from a solution of CuSO by the same current flowing for the same time would be 15.9 g (option c).
- Current liberates 0.504 g of hydrogen in 2 hours
To find:
- The amount of copper liberated from a solution of CuSO by the same current flowing for the same time
Solution:
1. Calculate the amount of charge that flows through the circuit:
- Current = 0.504 g / (2 hours x 3600 s/hour) = 7 x 10^-5 A
- Charge = Current x Time = 7 x 10^-5 A x 2 hours x 3600 s/hour = 0.504 C
2. Calculate the amount of copper liberated:
- The chemical equation for the liberation of copper from CuSO4 is:
CuSO4 + 2e- → Cu + SO4^2-
- From the equation, it can be seen that 2 electrons are required to liberate 1 mole of copper
- The molar mass of CuSO4 is 159.61 g/mol, which means that 1 mole of CuSO4 contains 1 mole of copper
- The amount of copper liberated can be calculated as follows:
- 1 mole of copper = 2 x 96500 C (since 1 mole of electrons carries a charge of 2 x 96500 C)
- Amount of copper liberated = (0.504 C / 2 x 96500 C) x 63.55 g/mol
= 0.000263 moles x 63.55 g/mol
= 0.0167 g
3. Round off the answer to 3 significant figures:
- The answer is 0.0167 g, which rounds off to 0.0159 g (since the third significant figure is less than 5)
Therefore, the amount of copper liberated from a solution of CuSO by the same current flowing for the same time would be 15.9 g (option c).
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A current liberates 0.504 g of hydrogen in 2 hours, the amount of copper liberated from a solution of CuSO₄ by the same current flowing for the same time would bea)31.8 gb)63.6 gc)15.9 gd)6.36 gCorrect answer is option 'C'. Can you explain this answer?
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A current liberates 0.504 g of hydrogen in 2 hours, the amount of copper liberated from a solution of CuSO₄ by the same current flowing for the same time would bea)31.8 gb)63.6 gc)15.9 gd)6.36 gCorrect answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A current liberates 0.504 g of hydrogen in 2 hours, the amount of copper liberated from a solution of CuSO₄ by the same current flowing for the same time would bea)31.8 gb)63.6 gc)15.9 gd)6.36 gCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A current liberates 0.504 g of hydrogen in 2 hours, the amount of copper liberated from a solution of CuSO₄ by the same current flowing for the same time would bea)31.8 gb)63.6 gc)15.9 gd)6.36 gCorrect answer is option 'C'. Can you explain this answer?.
A current liberates 0.504 g of hydrogen in 2 hours, the amount of copper liberated from a solution of CuSO₄ by the same current flowing for the same time would bea)31.8 gb)63.6 gc)15.9 gd)6.36 gCorrect answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A current liberates 0.504 g of hydrogen in 2 hours, the amount of copper liberated from a solution of CuSO₄ by the same current flowing for the same time would bea)31.8 gb)63.6 gc)15.9 gd)6.36 gCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A current liberates 0.504 g of hydrogen in 2 hours, the amount of copper liberated from a solution of CuSO₄ by the same current flowing for the same time would bea)31.8 gb)63.6 gc)15.9 gd)6.36 gCorrect answer is option 'C'. Can you explain this answer?.
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A current liberates 0.504 g of hydrogen in 2 hours, the amount of copper liberated from a solution of CuSO₄ by the same current flowing for the same time would bea)31.8 gb)63.6 gc)15.9 gd)6.36 gCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for A current liberates 0.504 g of hydrogen in 2 hours, the amount of copper liberated from a solution of CuSO₄ by the same current flowing for the same time would bea)31.8 gb)63.6 gc)15.9 gd)6.36 gCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of A current liberates 0.504 g of hydrogen in 2 hours, the amount of copper liberated from a solution of CuSO₄ by the same current flowing for the same time would bea)31.8 gb)63.6 gc)15.9 gd)6.36 gCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
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