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If 4 g steam at 100 degree celsius is passed in a container having 100 g of ice at 0 degree celsius, then final temperature of mixture is (1) 2 degree celsius (2) 4 degree celsius (3) 10 degreecelsius (4) 0 degree celsius?
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If 4 g steam at 100 degree celsius is passed in a container having 100...
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If 4 g steam at 100 degree celsius is passed in a container having 100...
Answer:
Given:
- Mass of steam (m1) = 4 g
- Temperature of steam (t1) = 100°C
- Mass of ice (m2) = 100 g
- Temperature of ice (t2) = 0°C
Assumptions:
- The heat transfer between the steam and the ice occurs in an isolated system, with no heat exchange with the surroundings.
- The latent heat of fusion of ice is ignored, assuming that the ice remains at 0°C throughout the process.
Calculating the heat lost by steam:
The heat lost by the steam can be calculated using the formula:
Q = m1 * c1 * (t1 - t)
Where:
- Q is the heat lost
- m1 is the mass of steam
- c1 is the specific heat capacity of steam
- t1 is the initial temperature of steam
- t is the final temperature of the mixture
Calculating the heat gained by ice:
The heat gained by the ice can be calculated using the formula:
Q = m2 * c2 * (t - t2)
Where:
- Q is the heat gained
- m2 is the mass of ice
- c2 is the specific heat capacity of ice
- t is the final temperature of the mixture
- t2 is the initial temperature of ice
Setting the heat lost equal to the heat gained:
Since the heat lost by the steam is equal to the heat gained by the ice, we can equate the two equations:
m1 * c1 * (t1 - t) = m2 * c2 * (t - t2)
Simplifying the equation:
Substituting the given values, we get:
4 * 2.03 * (100 - t) = 100 * 2.09 * (t - 0)
Solving for t:
Simplifying the equation further, we get:
(100 - t) / (t - 0) = (100 * 2.09) / (4 * 2.03)
Solving this equation, we find:
t ≈ 3.9°C
Final temperature of the mixture:
Therefore, the final temperature of the mixture is approximately 3.9°C.
Answer:
The final temperature of the mixture is approximately 4 degrees Celsius. (Option 2)
Given:
- Mass of steam (m1) = 4 g
- Temperature of steam (t1) = 100°C
- Mass of ice (m2) = 100 g
- Temperature of ice (t2) = 0°C
Assumptions:
- The heat transfer between the steam and the ice occurs in an isolated system, with no heat exchange with the surroundings.
- The latent heat of fusion of ice is ignored, assuming that the ice remains at 0°C throughout the process.
Calculating the heat lost by steam:
The heat lost by the steam can be calculated using the formula:
Q = m1 * c1 * (t1 - t)
Where:
- Q is the heat lost
- m1 is the mass of steam
- c1 is the specific heat capacity of steam
- t1 is the initial temperature of steam
- t is the final temperature of the mixture
Calculating the heat gained by ice:
The heat gained by the ice can be calculated using the formula:
Q = m2 * c2 * (t - t2)
Where:
- Q is the heat gained
- m2 is the mass of ice
- c2 is the specific heat capacity of ice
- t is the final temperature of the mixture
- t2 is the initial temperature of ice
Setting the heat lost equal to the heat gained:
Since the heat lost by the steam is equal to the heat gained by the ice, we can equate the two equations:
m1 * c1 * (t1 - t) = m2 * c2 * (t - t2)
Simplifying the equation:
Substituting the given values, we get:
4 * 2.03 * (100 - t) = 100 * 2.09 * (t - 0)
Solving for t:
Simplifying the equation further, we get:
(100 - t) / (t - 0) = (100 * 2.09) / (4 * 2.03)
Solving this equation, we find:
t ≈ 3.9°C
Final temperature of the mixture:
Therefore, the final temperature of the mixture is approximately 3.9°C.
Answer:
The final temperature of the mixture is approximately 4 degrees Celsius. (Option 2)
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If 4 g steam at 100 degree celsius is passed in a container having 100 g of ice at 0 degree celsius, then final temperature of mixture is (1) 2 degree celsius (2) 4 degree celsius (3) 10 degreecelsius (4) 0 degree celsius?
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If 4 g steam at 100 degree celsius is passed in a container having 100 g of ice at 0 degree celsius, then final temperature of mixture is (1) 2 degree celsius (2) 4 degree celsius (3) 10 degreecelsius (4) 0 degree celsius? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about If 4 g steam at 100 degree celsius is passed in a container having 100 g of ice at 0 degree celsius, then final temperature of mixture is (1) 2 degree celsius (2) 4 degree celsius (3) 10 degreecelsius (4) 0 degree celsius? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If 4 g steam at 100 degree celsius is passed in a container having 100 g of ice at 0 degree celsius, then final temperature of mixture is (1) 2 degree celsius (2) 4 degree celsius (3) 10 degreecelsius (4) 0 degree celsius?.
If 4 g steam at 100 degree celsius is passed in a container having 100 g of ice at 0 degree celsius, then final temperature of mixture is (1) 2 degree celsius (2) 4 degree celsius (3) 10 degreecelsius (4) 0 degree celsius? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about If 4 g steam at 100 degree celsius is passed in a container having 100 g of ice at 0 degree celsius, then final temperature of mixture is (1) 2 degree celsius (2) 4 degree celsius (3) 10 degreecelsius (4) 0 degree celsius? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If 4 g steam at 100 degree celsius is passed in a container having 100 g of ice at 0 degree celsius, then final temperature of mixture is (1) 2 degree celsius (2) 4 degree celsius (3) 10 degreecelsius (4) 0 degree celsius?.
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