Introduction:
In order to determine which electric bulb has a greater resistance between bulb A and bulb B, we need to analyze the power and voltage ratings of both bulbs. Resistance can be calculated using Ohm's Law, which states that resistance (R) is equal to voltage (V) divided by current (I), or R = V/I.

Analysis:
Let's break down the given information and analyze it step by step:

Bulb A:
- Power rating: 40 W
- Voltage rating: 220 V

Bulb B:
- Power rating: 60 W
- Voltage rating: 220 V

Determining resistance:
Resistance can be calculated using the formula R = V/I. Since we don't have the current values, we need to find a way to calculate it.

Using power and voltage:
We can use the given power and voltage ratings to calculate the current using the formula: P = VI. Rearranging the formula, we get: I = P/V.

Calculating current for bulb A:
For bulb A, P = 40 W and V = 220 V. Plugging these values into the formula, we get: I = 40/220 = 0.18 A.

Calculating current for bulb B:
Similarly, for bulb B, P = 60 W and V = 220 V. Plugging these values into the formula, we get: I = 60/220 = 0.27 A.

Calculating resistance for bulb A:
Now that we have the current value for bulb A, we can calculate its resistance using Ohm's Law. R = V/I = 220/0.18 = 1222.22 ohms.

Calculating resistance for bulb B:
Similarly, for bulb B, R = V/I = 220/0.27 = 814.81 ohms.

Comparison:
After calculating the resistance values for both bulbs, we can observe that bulb A has a resistance of 1222.22 ohms, while bulb B has a resistance of 814.81 ohms.

Conclusion:
Comparing the two resistance values, we can conclude that bulb A has a greater resistance than bulb B.

Which of two bulbs rated 40w 220v and 60w 220v has more resistance