What is the probability that an ordinary year has 53 sundays ?
An ordinary year has 365 days
A year has 52 weeks. Hence there will be 52 Sundays for sure.
52 weeks = 364 days
365 – 364 = 1 day
In an ordinary year, there will be 52 Sundays and 1 day will be left.
This one day can be, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.
Of these total 7 outcomes, the favourable outcome is 1.
Hence the probability of getting 53 Sundays = 1/7
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What is the probability that an ordinary year has 53 sundays ?
Probability of an Ordinary Year having 53 Sundays
The probability of an ordinary year having 53 Sundays can be calculated by analyzing the calendar structure and the number of days in a week.
Days in a Week
- In a week, there are 7 days.
- Sunday is one of the days in a week.
Number of Days in a Year
- An ordinary year has 365 days.
Calculation
- To determine the number of Sundays in a year, we divide 365 by 7 (days in a week).
- 365 divided by 7 equals 52 with a remainder of 1.
- This means that there are 52 full weeks in a year and 1 remaining day.
- If the remaining day is a Sunday, then the year will have 53 Sundays.
Probability Calculation
- The probability of the remaining day being a Sunday is 1 out of 7, as there are 7 days in a week.
- Therefore, the probability of an ordinary year having 53 Sundays is 1/7 or approximately 0.143.
In conclusion, the probability of an ordinary year having 53 Sundays is 1/7 or approximately 0.143. This calculation is based on the number of days in a year, days in a week, and the likelihood of the remaining day being a Sunday.