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The enthalpies of formation for C₂H₄(g), CO₂(g) and H₂O(l) at 25ºC and 1 atm. pressure be 52, -395 and -286 kJ mol⁻1 respectively. The enthalpy of combustion of C₂H₄(g) will bea)+1412 kJ mol⁻1b)-1412 kJ mol⁻1c)+141.2 kJ mol⁻1d)-141.2 kJ mol⁻1Correct answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The enthalpies of formation for C₂H₄(g), CO₂(g) and H₂O(l) at 25ºC and 1 atm. pressure be 52, -395 and -286 kJ mol⁻1 respectively. The enthalpy of combustion of C₂H₄(g) will bea)+1412 kJ mol⁻1b)-1412 kJ mol⁻1c)+141.2 kJ mol⁻1d)-141.2 kJ mol⁻1Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The enthalpies of formation for C₂H₄(g), CO₂(g) and H₂O(l) at 25ºC and 1 atm. pressure be 52, -395 and -286 kJ mol⁻1 respectively. The enthalpy of combustion of C₂H₄(g) will bea)+1412 kJ mol⁻1b)-1412 kJ mol⁻1c)+141.2 kJ mol⁻1d)-141.2 kJ mol⁻1Correct answer is option 'B'. Can you explain this answer?.

Solutions for The enthalpies of formation for C₂H₄(g), CO₂(g) and H₂O(l) at 25ºC and 1 atm. pressure be 52, -395 and -286 kJ mol⁻1 respectively. The enthalpy of combustion of C₂H₄(g) will bea)+1412 kJ mol⁻1b)-1412 kJ mol⁻1c)+141.2 kJ mol⁻1d)-141.2 kJ mol⁻1Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET. Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.

Here you can find the meaning of The enthalpies of formation for C₂H₄(g), CO₂(g) and H₂O(l) at 25ºC and 1 atm. pressure be 52, -395 and -286 kJ mol⁻1 respectively. The enthalpy of combustion of C₂H₄(g) will bea)+1412 kJ mol⁻1b)-1412 kJ mol⁻1c)+141.2 kJ mol⁻1d)-141.2 kJ mol⁻1Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of The enthalpies of formation for C₂H₄(g), CO₂(g) and H₂O(l) at 25ºC and 1 atm. pressure be 52, -395 and -286 kJ mol⁻1 respectively. The enthalpy of combustion of C₂H₄(g) will bea)+1412 kJ mol⁻1b)-1412 kJ mol⁻1c)+141.2 kJ mol⁻1d)-141.2 kJ mol⁻1Correct answer is option 'B'. Can you explain this answer?, a detailed solution for The enthalpies of formation for C₂H₄(g), CO₂(g) and H₂O(l) at 25ºC and 1 atm. pressure be 52, -395 and -286 kJ mol⁻1 respectively. The enthalpy of combustion of C₂H₄(g) will bea)+1412 kJ mol⁻1b)-1412 kJ mol⁻1c)+141.2 kJ mol⁻1d)-141.2 kJ mol⁻1Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of The enthalpies of formation for C₂H₄(g), CO₂(g) and H₂O(l) at 25ºC and 1 atm. pressure be 52, -395 and -286 kJ mol⁻1 respectively. The enthalpy of combustion of C₂H₄(g) will bea)+1412 kJ mol⁻1b)-1412 kJ mol⁻1c)+141.2 kJ mol⁻1d)-141.2 kJ mol⁻1Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice The enthalpies of formation for C₂H₄(g), CO₂(g) and H₂O(l) at 25ºC and 1 atm. pressure be 52, -395 and -286 kJ mol⁻1 respectively. The enthalpy of combustion of C₂H₄(g) will bea)+1412 kJ mol⁻1b)-1412 kJ mol⁻1c)+141.2 kJ mol⁻1d)-141.2 kJ mol⁻1Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice NEET tests.