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A simple harmonic motion has an amplitude A and time period T. Time required to travel from x=A to x=A/2 is: (1) T/6 (2) T/4 (3) T/3 (4) T/4?
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Explanation of Time Required to Travel from x=A to x=A/2 in Simple Harmonic Motion


Definition of Simple Harmonic Motion

Simple harmonic motion is a type of periodic motion where the restoring force is directly proportional to the displacement and is always directed towards the mean position.

Formula for Time Period of Simple Harmonic Motion

The time period of simple harmonic motion is given by the formula:
T = 2π√(m/k)
where T is the time period, m is the mass of the object undergoing simple harmonic motion and k is the spring constant.

Formula for Amplitude of Simple Harmonic Motion

The amplitude of simple harmonic motion is the maximum displacement of the object from its mean position. It is denoted by A.

Formula for Displacement of Simple Harmonic Motion

The displacement of an object undergoing simple harmonic motion can be represented by the formula:
x = A cos(2πt/T)
where x is the displacement at time t, A is the amplitude and T is the time period.

Calculation of Time Required to Travel from x=A to x=A/2

To calculate the time required to travel from x=A to x=A/2, we need to find the time taken for the displacement to change from A to A/2. We can do this by equating the displacement equation to A/2 and solving for t:
A/2 = A cos(2πt/T)
cos(2πt/T) = 1/2
2πt/T = π/3
t = T/6

Answer

Therefore, the time required to travel from x=A to x=A/2 in simple harmonic motion is T/6.
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