**Calculation of Charge Flowing**

To calculate the amount of charge flowing through the electric iron, we need to use the formula:

Charge (Q) = Current (I) × Time (t)

Given that the current is 1A and the time is 2 hours, we can substitute these values into the formula to find the charge:

Q = 1A × 2 hours

The unit of time needs to be converted to seconds, as the unit of current is in Amperes (A) and the unit of charge is in Coulombs (C). Since there are 3600 seconds in one hour, we can convert the time as follows:

Q = 1A × 2 hours × 3600 seconds/hour

Q = 1A × 2 × 3600 C

Q = 7200 C

Therefore, the amount of charge flowing through the electric iron in two hours is 7200 Coulombs.

**Effect of Voltage Change on Current Flowing**

When the voltage is changed to 400V, it will make a difference to the current flowing through the electric iron. This is because the relationship between voltage, current, and resistance is governed by Ohm's Law, which states:

Voltage (V) = Current (I) × Resistance (R)

In this case, the resistance of the electric iron remains constant. So, when the voltage is increased from 100V to 400V, the current flowing through the iron will also change. To understand this, we can rearrange Ohm's Law:

Current (I) = Voltage (V) / Resistance (R)

Since resistance is constant, we can see that the current is directly proportional to the voltage. Therefore, when the voltage is increased, the current will also increase.

In conclusion, changing the voltage from 100V to 400V will indeed make a difference to the current flowing through the electric iron. The current will increase proportionally to the increase in voltage, assuming the resistance remains constant.

Given:-.
I= 1A
V=100V
t= 2 hrs.= 2*60*60 s
Q= ?


CASE=|


Q=It
= 1 * 2*60*60
= 7200 C


CASE=. ||

... V=IR
R= 100V/1A
R= 100 ohm


now....
I = V/R
= 400/100
I= 4 A..
.•. current is increasing 4 times...