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At N.T.P. one mole of diatomic gas is compressed adiabatically to half of its volume (γ = 1.41). The work done on gas will be
  • a)
    1280 J
  • b)
    1610 J
  • c)
    1815 J
  • d)
    2025 J
Correct answer is option 'C'. Can you explain this answer?
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At N.T.P. one mole of diatomic gas is compressed adiabatically to half...
Assuming the compression is reversible and the gas behaves ideally).
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At N.T.P. one mole of diatomic gas is compressed adiabatically to half of its volume (γ = 1.41). The work done on gas will bea)1280 Jb)1610 Jc)1815 Jd)2025 JCorrect answer is option 'C'. Can you explain this answer?
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