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A solution containing As+3, Cd2+, Ni2+ and Zn2+ is made alkaline with dilute NH₄OH and treated with H₂S. The precipitate obtained will consist of :
- a)As₂S₃ and CdS
- b)CdS, NiS and ZnS
- c)NiS and ZnS
- d)NiS
Correct answer is option 'C'. Can you explain this answer?
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A solution containing As+3, Cd2+, Ni2+ and Zn2+is made alkaline with d...
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A solution containing As+3, Cd2+, Ni2+ and Zn2+is made alkaline with d...
The given solution contains As3+, Cd2+, Ni2+, and Zn2+ ions. When this solution is made alkaline by adding dilute NaOH, it results in the precipitation of metal sulfides when treated with H2S gas. Let's analyze the reaction step by step to understand why the precipitate consists of NiS and ZnS.
1. Formation of Amphoteric As(OH)3:
Upon adding dilute NaOH to the solution, As3+ ions react with OH- ions to form As(OH)3, which is an amphoteric compound. It can act as both an acid and a base.
As3+ + 3OH- → As(OH)3
2. Precipitation of CdS:
Cd2+ ions react with OH- ions to form Cd(OH)2, which is a white precipitate. This precipitate further reacts with H2S gas to form CdS, which is a yellow precipitate.
Cd2+ + 2OH- → Cd(OH)2
Cd(OH)2 + H2S → CdS↓ + 2H2O
3. Formation of Amphoteric Ni(OH)2:
Ni2+ ions react with OH- ions to form Ni(OH)2, which is an amphoteric compound similar to As(OH)3.
Ni2+ + 2OH- → Ni(OH)2
4. Formation of Zn(OH)2:
Zn2+ ions react with OH- ions to form Zn(OH)2, which is a white precipitate.
Zn2+ + 2OH- → Zn(OH)2
5. Precipitation of NiS and ZnS:
When the solution is treated with H2S gas, it reacts with the amphoteric Ni(OH)2 and Zn(OH)2 to form NiS and ZnS, respectively.
Ni(OH)2 + H2S → NiS↓ + 2H2O
Zn(OH)2 + H2S → ZnS↓ + 2H2O
Therefore, the precipitate obtained from the solution will consist of NiS and ZnS, which is the correct answer (option C). The other options are incorrect because they do not include both NiS and ZnS in the precipitate.
1. Formation of Amphoteric As(OH)3:
Upon adding dilute NaOH to the solution, As3+ ions react with OH- ions to form As(OH)3, which is an amphoteric compound. It can act as both an acid and a base.
As3+ + 3OH- → As(OH)3
2. Precipitation of CdS:
Cd2+ ions react with OH- ions to form Cd(OH)2, which is a white precipitate. This precipitate further reacts with H2S gas to form CdS, which is a yellow precipitate.
Cd2+ + 2OH- → Cd(OH)2
Cd(OH)2 + H2S → CdS↓ + 2H2O
3. Formation of Amphoteric Ni(OH)2:
Ni2+ ions react with OH- ions to form Ni(OH)2, which is an amphoteric compound similar to As(OH)3.
Ni2+ + 2OH- → Ni(OH)2
4. Formation of Zn(OH)2:
Zn2+ ions react with OH- ions to form Zn(OH)2, which is a white precipitate.
Zn2+ + 2OH- → Zn(OH)2
5. Precipitation of NiS and ZnS:
When the solution is treated with H2S gas, it reacts with the amphoteric Ni(OH)2 and Zn(OH)2 to form NiS and ZnS, respectively.
Ni(OH)2 + H2S → NiS↓ + 2H2O
Zn(OH)2 + H2S → ZnS↓ + 2H2O
Therefore, the precipitate obtained from the solution will consist of NiS and ZnS, which is the correct answer (option C). The other options are incorrect because they do not include both NiS and ZnS in the precipitate.
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A solution containing As+3, Cd2+, Ni2+ and Zn2+is made alkaline with dilute NH₄OH and treated with H₂S. The precipitate obtained will consist of :a)As₂S₃ and CdSb)CdS, NiS and ZnSc)NiS and ZnSd)NiSCorrect answer is option 'C'. Can you explain this answer?
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