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The edge length of the unit cell of body-centred lattice is 500 pm. If the radius of cation is 169 pm, then what is radius of anion?
- a)200 pm
- b)220 pm
- c)248 pm
- d)264 pm
Correct answer is option 'D'. Can you explain this answer?
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The edge length of the unit cell of body-centred lattice is 500 pm. If...
Body-Centered Lattice
A body-centered lattice is a type of crystal lattice in which an additional atom is located at the center of the unit cell. The unit cell is the smallest repeating unit of the crystal lattice.
Given values
- Edge length of the unit cell = 500 pm
- Radius of cation = 169 pm
Calculating radius of anion
To calculate the radius of anion, we need to first determine the relationship between the edge length of the unit cell and the radius of the cation.
In a body-centered lattice, the cation is located at each of the eight corners of the unit cell and one additional cation is located at the center of the unit cell. The anion is located at the center of each face of the unit cell.
The distance between the center of the unit cell and the center of the face of the unit cell is equal to half of the edge length. Therefore, the radius of the anion is equal to:
Radius of anion = (Edge length / 2) - Radius of cation
Radius of anion = (500 pm / 2) - 169 pm
Radius of anion = 264 pm
Therefore, the correct answer is option D, 264 pm.
A body-centered lattice is a type of crystal lattice in which an additional atom is located at the center of the unit cell. The unit cell is the smallest repeating unit of the crystal lattice.
Given values
- Edge length of the unit cell = 500 pm
- Radius of cation = 169 pm
Calculating radius of anion
To calculate the radius of anion, we need to first determine the relationship between the edge length of the unit cell and the radius of the cation.
In a body-centered lattice, the cation is located at each of the eight corners of the unit cell and one additional cation is located at the center of the unit cell. The anion is located at the center of each face of the unit cell.
The distance between the center of the unit cell and the center of the face of the unit cell is equal to half of the edge length. Therefore, the radius of the anion is equal to:
Radius of anion = (Edge length / 2) - Radius of cation
Radius of anion = (500 pm / 2) - 169 pm
Radius of anion = 264 pm
Therefore, the correct answer is option D, 264 pm.
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The edge length of the unit cell of body-centred lattice is 500 pm. If...
Actually for bcc structure root 3a/2=r(cation)+r(anion) so root 3=1.73 and a=500pm so put value 1.73*500/2=169+r(anion) =263.5
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The edge length of the unit cell of body-centred lattice is 500 pm. If the radius of cation is 169 pm, then what is radius of anion?a)200 pmb)220 pmc)248 pmd)264 pmCorrect answer is option 'D'. Can you explain this answer?
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