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If the ratio of specific heat of a gas at constant pressure to that at constant volume is γ, the change in internal energy of a mass of gas, when the volume changes from V to 2V at constant pressure p, is
  • a)
    R/(γ - 1)
  • b)
    pV
  • c)
    pV/(γ - 1)
  • d)
    γpV/(γ - 1)
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
If the ratio of specific heat of a gas at constant pressure to that at...
∆U=nCv∆T
Cp-Cv=R and Cp=YCv
YCv-Cv=R so Cv=R/Y-1
put Cv in ∆U
we get ∆U=nR∆T/Y-1 and PV=nR∆T
so we get ∆U=PV/Y-1
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Community Answer
If the ratio of specific heat of a gas at constant pressure to that at...
Not given in the question, we cannot determine the value of the ratio.
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If the ratio of specific heat of a gas at constant pressure to that at constant volume is γ, the change in internal energy of a mass of gas, when the volume changes from V to 2V at constant pressure p, isa)R/(γ - 1)b)pVc)pV/(γ - 1)d)γpV/(γ - 1)Correct answer is option 'C'. Can you explain this answer?
Question Description
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