NEET Exam > NEET Questions > Which of the following is odd one out?a)Potas...
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Which of the following is odd one out?
- a)Potassium ferricyanide
- b)Ferrous ammonium sulphate
- c)Potassium ferricynide
- d)Tetra-amminecopper(II) sulphate
Correct answer is option 'B'. Can you explain this answer?
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Which of the following is odd one out?a)Potassium ferricyanideb)Ferrou...
Odd One Out: Ferrous Ammonium Sulphate
Explanation:
The given options are all compounds of transition metals, but Ferrous Ammonium Sulphate is the odd one out. The reason is explained below.
a) Potassium Ferricyanide:
- Contains Fe in a +3 oxidation state.
- The cyanide group acts as a ligand and forms a coordination compound.
- The formula is K3[Fe(CN)6].
b) Ferrous Ammonium Sulphate:
- Contains Fe in a +2 oxidation state.
- The ammonium and sulphate group act as ligands and form a coordination compound.
- The formula is Fe(NH4)2(SO4)2.6H2O.
c) Potassium Ferricyanide:
- Contains Fe in a +3 oxidation state.
- The cyanide group acts as a ligand and forms a coordination compound.
- The formula is K4[Fe(CN)6].
d) Tetra-amminecopper(II) Sulphate:
- Contains Cu in a +2 oxidation state.
- The ammonia ligands act as ligands and form a coordination compound.
- The formula is [Cu(NH3)4](SO4).
Conclusion:
All the given options have transition metals as central atoms and coordinate compounds. But Ferrous Ammonium Sulphate is the odd one out because it contains Fe2+ ion whereas all other options contain Fe3+ or Cu2+ ion.
Explanation:
The given options are all compounds of transition metals, but Ferrous Ammonium Sulphate is the odd one out. The reason is explained below.
a) Potassium Ferricyanide:
- Contains Fe in a +3 oxidation state.
- The cyanide group acts as a ligand and forms a coordination compound.
- The formula is K3[Fe(CN)6].
b) Ferrous Ammonium Sulphate:
- Contains Fe in a +2 oxidation state.
- The ammonium and sulphate group act as ligands and form a coordination compound.
- The formula is Fe(NH4)2(SO4)2.6H2O.
c) Potassium Ferricyanide:
- Contains Fe in a +3 oxidation state.
- The cyanide group acts as a ligand and forms a coordination compound.
- The formula is K4[Fe(CN)6].
d) Tetra-amminecopper(II) Sulphate:
- Contains Cu in a +2 oxidation state.
- The ammonia ligands act as ligands and form a coordination compound.
- The formula is [Cu(NH3)4](SO4).
Conclusion:
All the given options have transition metals as central atoms and coordinate compounds. But Ferrous Ammonium Sulphate is the odd one out because it contains Fe2+ ion whereas all other options contain Fe3+ or Cu2+ ion.
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Which of the following is odd one out?a)Potassium ferricyanideb)Ferrou...
Option B is correct as rest all the other option A,C,D are coordination compounds while option B Is not
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