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In the crystalline solid MSO4.H2O of molar mass 250 g/mol, the percentage of anhydrous salt is 64 by weight. the value of n is?
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In the crystalline solid MSO4.H2O of molar mass 250 g/mol, the percent...

Calculation of 'n' in MSO4.H2O

- Given data:
- Molar mass of MSO4.H2O = 250 g/mol
- Percentage of anhydrous salt = 64%

- Let's assume the molar mass of anhydrous salt (MSO4) to be x g/mol and the molar mass of water (H2O) to be y g/mol.

- The molar mass of MSO4.H2O can be expressed as:
- 250 = x + y

- Since the percentage of anhydrous salt is 64%, the mass of anhydrous salt in 100 g of MSO4.H2O is:
- Mass of anhydrous salt = 64% of 100 g = 64 g

- The mass of water in 100 g of MSO4.H2O is:
- Mass of water = 100 g - 64 g = 36 g

- Now, we can set up the following equations based on the molar masses:
- x + y = 250
- 64x + 36y = 100

- Solving these equations, we find:
- x = 160 g/mol
- y = 90 g/mol

- Therefore, the molar mass of anhydrous salt (MSO4) is 160 g/mol, and the molar mass of water (H2O) is 90 g/mol.

- The formula for MSO4.H2O can be rewritten as:
- MSO4.1.25H2O

- Hence, the value of 'n' in MSO4.H2O is 1.25.
Community Answer
In the crystalline solid MSO4.H2O of molar mass 250 g/mol, the percent...
The ans is n =5
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In the crystalline solid MSO4.H2O of molar mass 250 g/mol, the percentage of anhydrous salt is 64 by weight. the value of n is?
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