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When equal volumes of two liquids are mixed, the specific gravity of mixture is 7/2 . When equal masses of same liquids are mixed the specific gravity of mixture is 12/7 . The specific gravities of two liquids are
  • a)
    1 and 6
  • b)
    2 and 6
  • c)
    2 and 4
  • d)
    3 and 6
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
When equal volumes of two liquids are mixed, the specific gravity of m...
Specific gravity=mass of liquid/volume of liquid



therefore, specific gravity=12/7×7/2

84/14
=6
Free Test
Community Answer
When equal volumes of two liquids are mixed, the specific gravity of m...
Correct option is b we HD explained this in following
Step-by-step explanation:
Let ρ₁ and ρ₂ be the specific gravity of two liquids
When equal volume is mixed then
specific gravity= ρ
which is given by formula
ρ= (ρ₁+ρ₂)/2
As it is given that specific gravity = 4
so
4= (ρ₁+ρ₂)/2
ρ₁+ρ₂ = 8   (i)
Now when equal masses are added
it is given by the formula
ρ= (2ρ₁ρ₂)/(ρ₁+ρ₂)
as ρ=3 so
3 (ρ₁+ρ₂)=(2ρ₁ρ₂)
3(8) =(2ρ₁ρ₂)
ρ₁ρ₂=
ρ₁ρ₂=12                                  (ii)
from equation (ii)
ρ₁=12/ρ₂
put it in (i)
12/ρ₂+ρ₂=8
ρ₂²+12=8ρ₂
ρ₂²+12-8ρ₂=0
ρ₂²-8ρ₂+12=0
using mid term breaking
ρ₂²-6ρ₂-2ρ₂+12=0
ρ₂(ρ₂-6)-2(ρ₂-6)=0
(ρ₂-6)(ρ₂-2)=0
so
ρ₂=6 or ρ₂=2
Now putting it in (i)
ρ₁=8-ρ₂
ρ₁=8-6 and ρ₁=8-2
ρ₁=2 or ρ₁=6
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When equal volumes of two liquids are mixed, the specific gravity of mixture is 7/2. When equal masses of same liquids are mixed the specific gravity of mixture is 12/7. The specific gravities of two liquids area)1 and 6b)2 and 6c)2 and 4d)3 and 6Correct answer is option 'A'. Can you explain this answer?
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