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A liquid of mass ‘m’ and specific heat ‘S’ is at temperature θ . Another liquid of mass 2m and specific heat S/2 is at 3θ. If these two liquids are mixed, resultant temperature of the mixture
  • a)
    θ/2
  • b)
    θ
  • c)
    2θ
  • d)
    3θ/2
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A liquid of mass ‘m’ and specific heat ‘S’ is ...
Energy of first liquid + energy of 2nd liquid = energy of mixed liquid of 1st and 2nd

energy of first liquid = mc � 2t = mc2t

energy of 2nd liquid = (m/2)(2c)t = mct

specific heat of mixture, C = (mc + m/2 � 2c)/(m + m/2) = 2mc/(3m/2) = 4c/3

Let resulting temperature of mixture is T

then, energy of mixture = (m + m/2) � (4c/3) � T

now, 2mct + mct = (3m/2) � (4c/3) � T

or, 3mct = 2mc � T

or, T = 3t/2

hence , resulting temperature of mixture is 3t/2.
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A liquid of mass ‘m’ and specific heat ‘S’ is at temperature θ. Another liquid of mass 2m and specific heat S/2is at 3θ. If these two liquids are mixed, resultant temperature of the mixturea)θ/2b)θc)2θd)3θ/2Correct answer is option 'C'. Can you explain this answer?
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