NEET Exam  >  NEET Questions  >  A 10 μF capacitor is charged to a potentia... Start Learning for Free
A 10 μF capacitor is charged to a potential difference 50 V and it is then connected to another uncharged capacitor in parallel. If common potential difference becomes 20 V, then capacitance of the second capacitor is
  • a)
    10 μF
  • b)
    15 μF
  • c)
    20 μF
  • d)
    30 μF
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
A 10 μF capacitor is charged to a potential difference 50 V and it ...
Attention NEET Students!
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.
Explore Courses for NEET exam

Top Courses for NEET

A 10 μF capacitor is charged to a potential difference 50 V and it is then connected to another uncharged capacitor in parallel. If common potential difference becomes 20 V, then capacitance of the second capacitor isa)10 μFb)15 μFc)20 μFd)30 μFCorrect answer is option 'B'. Can you explain this answer?
Question Description
A 10 μF capacitor is charged to a potential difference 50 V and it is then connected to another uncharged capacitor in parallel. If common potential difference becomes 20 V, then capacitance of the second capacitor isa)10 μFb)15 μFc)20 μFd)30 μFCorrect answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A 10 μF capacitor is charged to a potential difference 50 V and it is then connected to another uncharged capacitor in parallel. If common potential difference becomes 20 V, then capacitance of the second capacitor isa)10 μFb)15 μFc)20 μFd)30 μFCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 10 μF capacitor is charged to a potential difference 50 V and it is then connected to another uncharged capacitor in parallel. If common potential difference becomes 20 V, then capacitance of the second capacitor isa)10 μFb)15 μFc)20 μFd)30 μFCorrect answer is option 'B'. Can you explain this answer?.
Solutions for A 10 μF capacitor is charged to a potential difference 50 V and it is then connected to another uncharged capacitor in parallel. If common potential difference becomes 20 V, then capacitance of the second capacitor isa)10 μFb)15 μFc)20 μFd)30 μFCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET. Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of A 10 μF capacitor is charged to a potential difference 50 V and it is then connected to another uncharged capacitor in parallel. If common potential difference becomes 20 V, then capacitance of the second capacitor isa)10 μFb)15 μFc)20 μFd)30 μFCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of A 10 μF capacitor is charged to a potential difference 50 V and it is then connected to another uncharged capacitor in parallel. If common potential difference becomes 20 V, then capacitance of the second capacitor isa)10 μFb)15 μFc)20 μFd)30 μFCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for A 10 μF capacitor is charged to a potential difference 50 V and it is then connected to another uncharged capacitor in parallel. If common potential difference becomes 20 V, then capacitance of the second capacitor isa)10 μFb)15 μFc)20 μFd)30 μFCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of A 10 μF capacitor is charged to a potential difference 50 V and it is then connected to another uncharged capacitor in parallel. If common potential difference becomes 20 V, then capacitance of the second capacitor isa)10 μFb)15 μFc)20 μFd)30 μFCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice A 10 μF capacitor is charged to a potential difference 50 V and it is then connected to another uncharged capacitor in parallel. If common potential difference becomes 20 V, then capacitance of the second capacitor isa)10 μFb)15 μFc)20 μFd)30 μFCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice NEET tests.
Explore Courses for NEET exam

Top Courses for NEET

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev