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The orbital velocity of an artificial satellite in a circular orbit just above the earth's surface is V. For a satellite orbiting at an altitude of half of the earth's radius, the orbital velocity is
- a)3/2 V
- b)√3/2 V
- c)√2/3 V
- d)2/3 V
Correct answer is option 'C'. Can you explain this answer?
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Most Upvoted Answer
The orbital velocity of an artificial satellite in a circular orbit ju...
Given,for artificial satellite, orbital velocity=v
for satellite at h=R/2
new orbital velocity=v`
Wkt,v`=√GM/R+h
=√GM/R+R/2
=√2/3 × √GM/R
=√2/3 × v
=√2/3v
Ans:- 'C'
Hope this helps u(•‿•)
for satellite at h=R/2
new orbital velocity=v`
Wkt,v`=√GM/R+h
=√GM/R+R/2
=√2/3 × √GM/R
=√2/3 × v
=√2/3v
Ans:- 'C'
Hope this helps u(•‿•)
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Community Answer
The orbital velocity of an artificial satellite in a circular orbit ju...
To find the orbital velocity at an altitude of half of the earth's radius, we can use the formula for orbital velocity:
V = sqrt(GM/R)
Where:
V = orbital velocity
G = gravitational constant
M = mass of the earth
R = radius of the orbit
At an altitude of half of the earth's radius, the radius of the orbit would be 1.5 times the radius of the earth (since the altitude is added to the radius). Therefore, the radius of the orbit (R) would be 1.5R.
Substituting this value into the formula, we get:
V = sqrt(GM/(1.5R))
To find the ratio of the orbital velocity at an altitude of half of the earth's radius to the orbital velocity just above the earth's surface, we can divide the two equations:
V / (3/2 V) = sqrt(GM/(1.5R)) / sqrt(GM/R)
Simplifying this expression, we get:
V / (3/2 V) = sqrt((GM/(1.5R)) / (GM/R))
V / (3/2 V) = sqrt((GM/(1.5R)) * (R/GM))
V / (3/2 V) = sqrt(1.5)
Therefore, the orbital velocity at an altitude of half of the earth's radius is 3/2 V.
Answer: a) 3/2 V
V = sqrt(GM/R)
Where:
V = orbital velocity
G = gravitational constant
M = mass of the earth
R = radius of the orbit
At an altitude of half of the earth's radius, the radius of the orbit would be 1.5 times the radius of the earth (since the altitude is added to the radius). Therefore, the radius of the orbit (R) would be 1.5R.
Substituting this value into the formula, we get:
V = sqrt(GM/(1.5R))
To find the ratio of the orbital velocity at an altitude of half of the earth's radius to the orbital velocity just above the earth's surface, we can divide the two equations:
V / (3/2 V) = sqrt(GM/(1.5R)) / sqrt(GM/R)
Simplifying this expression, we get:
V / (3/2 V) = sqrt((GM/(1.5R)) / (GM/R))
V / (3/2 V) = sqrt((GM/(1.5R)) * (R/GM))
V / (3/2 V) = sqrt(1.5)
Therefore, the orbital velocity at an altitude of half of the earth's radius is 3/2 V.
Answer: a) 3/2 V
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The orbital velocity of an artificial satellite in a circular orbit just above the earths surface is V. For a satellite orbiting at an altitude of half of the earths radius, the orbital velocity isa)3/2 Vb)√3/2 Vc)√2/3 Vd)2/3 VCorrect answer is option 'C'. Can you explain this answer?
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The orbital velocity of an artificial satellite in a circular orbit just above the earths surface is V. For a satellite orbiting at an altitude of half of the earths radius, the orbital velocity isa)3/2 Vb)√3/2 Vc)√2/3 Vd)2/3 VCorrect answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The orbital velocity of an artificial satellite in a circular orbit just above the earths surface is V. For a satellite orbiting at an altitude of half of the earths radius, the orbital velocity isa)3/2 Vb)√3/2 Vc)√2/3 Vd)2/3 VCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The orbital velocity of an artificial satellite in a circular orbit just above the earths surface is V. For a satellite orbiting at an altitude of half of the earths radius, the orbital velocity isa)3/2 Vb)√3/2 Vc)√2/3 Vd)2/3 VCorrect answer is option 'C'. Can you explain this answer?.
The orbital velocity of an artificial satellite in a circular orbit just above the earths surface is V. For a satellite orbiting at an altitude of half of the earths radius, the orbital velocity isa)3/2 Vb)√3/2 Vc)√2/3 Vd)2/3 VCorrect answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The orbital velocity of an artificial satellite in a circular orbit just above the earths surface is V. For a satellite orbiting at an altitude of half of the earths radius, the orbital velocity isa)3/2 Vb)√3/2 Vc)√2/3 Vd)2/3 VCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The orbital velocity of an artificial satellite in a circular orbit just above the earths surface is V. For a satellite orbiting at an altitude of half of the earths radius, the orbital velocity isa)3/2 Vb)√3/2 Vc)√2/3 Vd)2/3 VCorrect answer is option 'C'. Can you explain this answer?.
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