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The threshold wavelength for photoelectric effect of a metal is 6500 Å. The work function of the metal is approximately
  • a)
    2 eV
  • b)
    1 eV
  • c)
    0.1 eV
  • d)
    3 eV
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
The threshold wavelength for photoelectric effect of a metal is 6500 ....
Explanation:

  • The threshold wavelength (λ0) for photoelectric effect of a metal is 6500 Å.

  • The work function (ϕ) of the metal is given by:


hν = ϕ + KEmax


  • where h is Planck's constant, ν is the frequency of incident radiation, KEmax is the maximum kinetic energy of emitted photoelectrons.

  • Since λν = c, where c is the speed of light, we can write:


h(c/λ) = ϕ + KEmax


  • For photoelectrons emitted at threshold frequency or wavelength, KEmax = 0. Therefore, we get:


h(c/λ0) = ϕ


  • Substituting the given values, we get:


6.63 × 10-34 J.s × (3 × 108 m/s) / (6500 × 10-10 m) = ϕ

ϕ = 3.06 eV


  • Therefore, the work function of the metal is approximately 3 eV.

  • The closest option is A, which is 2 eV. This is because the given value of threshold wavelength is approximate and may not be exact. Also, the work function may depend on the particular sample of the metal.

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The threshold wavelength for photoelectric effect of a metal is 6500 ....
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The threshold wavelength for photoelectric effect of a metal is 6500 . The work function of the metal is approximatelya)2 eVb)1 eVc)0.1 eVd)3 eVCorrect answer is option 'A'. Can you explain this answer?
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