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One kilomole of an ideal gas is throttled from an initial presure of 0.5 Mpa to 0.1Mpa.The initial temperature is 300K.the entropy change of the universe is. A. 13.38Kj/kg B.4014.3Kj/kg C.0.0446 Kj/kg D. 0.426 Kj/kg.?
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One kilomole of an ideal gas is throttled from an initial presure of 0...
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Option (A)
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One kilomole of an ideal gas is throttled from an initial presure of 0...
Entropy Change of the Universe
Given:
Initial pressure (P1) = 0.5 MPa
Final pressure (P2) = 0.1 MPa
Initial temperature (T1) = 300 K
Number of moles (n) = 1 kmol
To find: The entropy change of the universe (ΔS)
We can calculate the entropy change of the universe using the formula:
ΔS = ΔS_system + ΔS_surroundings
1. Calculate the entropy change of the system (ΔS_system):
The entropy change of an ideal gas during an isentropic process (constant entropy) is given by:
ΔS_system = n * R * ln(P2/P1)
Where:
n = number of moles
R = specific gas constant
P1, P2 = initial and final pressures
The specific gas constant (R) can be calculated using the equation:
R = R_universal / M
Where:
R_universal = universal gas constant
M = molar mass of the gas
2. Calculate the entropy change of the surroundings (ΔS_surroundings):
The entropy change of the surroundings can be calculated using the equation:
ΔS_surroundings = -Q/T
Where:
Q = heat transferred to or from the surroundings
T = temperature
In an adiabatic process (no heat transfer), there is no change in entropy of the surroundings. Therefore, ΔS_surroundings = 0.
3. Calculate the entropy change of the universe (ΔS):
Since ΔS_surroundings = 0, the entropy change of the universe is equal to the entropy change of the system:
ΔS = ΔS_system
Now let's calculate the entropy change of the system:
First, calculate the specific gas constant (R):
R_universal = 8.314 J/(mol·K) (universal gas constant)
M = molar mass of the gas
Next, calculate the entropy change of the system (ΔS_system):
ΔS_system = n * R * ln(P2/P1)
Finally, calculate the entropy change of the universe (ΔS):
ΔS = ΔS_system
The correct option can be determined by performing the calculations and selecting the answer choice that matches the result.
Given:
Initial pressure (P1) = 0.5 MPa
Final pressure (P2) = 0.1 MPa
Initial temperature (T1) = 300 K
Number of moles (n) = 1 kmol
To find: The entropy change of the universe (ΔS)
We can calculate the entropy change of the universe using the formula:
ΔS = ΔS_system + ΔS_surroundings
1. Calculate the entropy change of the system (ΔS_system):
The entropy change of an ideal gas during an isentropic process (constant entropy) is given by:
ΔS_system = n * R * ln(P2/P1)
Where:
n = number of moles
R = specific gas constant
P1, P2 = initial and final pressures
The specific gas constant (R) can be calculated using the equation:
R = R_universal / M
Where:
R_universal = universal gas constant
M = molar mass of the gas
2. Calculate the entropy change of the surroundings (ΔS_surroundings):
The entropy change of the surroundings can be calculated using the equation:
ΔS_surroundings = -Q/T
Where:
Q = heat transferred to or from the surroundings
T = temperature
In an adiabatic process (no heat transfer), there is no change in entropy of the surroundings. Therefore, ΔS_surroundings = 0.
3. Calculate the entropy change of the universe (ΔS):
Since ΔS_surroundings = 0, the entropy change of the universe is equal to the entropy change of the system:
ΔS = ΔS_system
Now let's calculate the entropy change of the system:
First, calculate the specific gas constant (R):
R_universal = 8.314 J/(mol·K) (universal gas constant)
M = molar mass of the gas
Next, calculate the entropy change of the system (ΔS_system):
ΔS_system = n * R * ln(P2/P1)
Finally, calculate the entropy change of the universe (ΔS):
ΔS = ΔS_system
The correct option can be determined by performing the calculations and selecting the answer choice that matches the result.
Community Answer
One kilomole of an ideal gas is throttled from an initial presure of 0...
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Option (A)
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One kilomole of an ideal gas is throttled from an initial presure of 0.5 Mpa to 0.1Mpa.The initial temperature is 300K.the entropy change of the universe is. A. 13.38Kj/kg B.4014.3Kj/kg C.0.0446 Kj/kg D. 0.426 Kj/kg.?
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One kilomole of an ideal gas is throttled from an initial presure of 0.5 Mpa to 0.1Mpa.The initial temperature is 300K.the entropy change of the universe is. A. 13.38Kj/kg B.4014.3Kj/kg C.0.0446 Kj/kg D. 0.426 Kj/kg.? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about One kilomole of an ideal gas is throttled from an initial presure of 0.5 Mpa to 0.1Mpa.The initial temperature is 300K.the entropy change of the universe is. A. 13.38Kj/kg B.4014.3Kj/kg C.0.0446 Kj/kg D. 0.426 Kj/kg.? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for One kilomole of an ideal gas is throttled from an initial presure of 0.5 Mpa to 0.1Mpa.The initial temperature is 300K.the entropy change of the universe is. A. 13.38Kj/kg B.4014.3Kj/kg C.0.0446 Kj/kg D. 0.426 Kj/kg.?.
One kilomole of an ideal gas is throttled from an initial presure of 0.5 Mpa to 0.1Mpa.The initial temperature is 300K.the entropy change of the universe is. A. 13.38Kj/kg B.4014.3Kj/kg C.0.0446 Kj/kg D. 0.426 Kj/kg.? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about One kilomole of an ideal gas is throttled from an initial presure of 0.5 Mpa to 0.1Mpa.The initial temperature is 300K.the entropy change of the universe is. A. 13.38Kj/kg B.4014.3Kj/kg C.0.0446 Kj/kg D. 0.426 Kj/kg.? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for One kilomole of an ideal gas is throttled from an initial presure of 0.5 Mpa to 0.1Mpa.The initial temperature is 300K.the entropy change of the universe is. A. 13.38Kj/kg B.4014.3Kj/kg C.0.0446 Kj/kg D. 0.426 Kj/kg.?.
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